X * y = 50
y = 50 / x
S = x + y = x + 50 / x
S` = 1 - 50 / x²
1 - 50 / x² = 0
50 / x² = 1
x² = 50
x = √ 50 = 5 √2
y = 50 / 5√2 = 5 √2
Answer:
Those numbers are: x = 5√2 and y = 5√2.
Lets write down what we know...
Laura walks 3/5 mile to school everyday
Laura=3/5mile
Isaiah's walk is 3 times as long as Lauras, so
Isaiah=Laura*3
We know how far Lauras walk is so we can solve for Isaiah's walk
Isaiah=3/5*3 (or Isaiah=3/5+3/5+3/5 if thats easier for you to solve for)
Isaiah=9/5 miles
Now we know the answer! Great, Isaiah walks 9/5 miles to school each day. But 9/5 is an improper fraction, so lets convert it to a mixed number.
9/5=
To solve for this, we have to find out how many times 5 can go into 9. 5 goes into 9 one time with a remainder of 4, so we can write the mixed number as.
9/5= 1 4/5
Isaiah walks 9/5miles or 1 4/5 miles. Both are correct.
I'm not sure if you need the answer or just the steps to start, so I will just give u the steps. First, just take a step back and take it one step at a time. Once you have an idea of how the two triangles are congruent, make 2 columns, one with statements and one with reasons. On the statements side, put given information and what you learn along the way, like if it is given x=y, and y=z, then what you can put down after that is x=z. On the reasons side, put the properties or formulas you used to reach your solution. For instance, if x=y and y=z, x=z by the Transitive property of equality. Proofs are time consuming, tedious and utterly frustrating. Just take it slowly and you will be fine.
Answer:
See below.
Step-by-step explanation:
<u>Given</u> :
- ΔMAL ≅ ΔDLA, DL = MA, ∠MAL = ∠DLA
- ∠M = 30°
- DL = (2x + 10) cm
- MA = (3x - 2) cm
- AL = (x + 5) cm
<u>To Find</u> :
- DL
- AL
- ∠DLA
- ∠ADL
<u>Solving</u> :
- DL = MA
- 2x + 10 = 3x - 2
- x = 12
- <u>DL = 24 + 10 = 34 cm</u>
- AL = x + 5
- AL = 12 + 5
- <u>AL = 17 cm</u>
- ∠DLA = 180° - 90° - 30° = 180° - 120° = <u>60°</u>
F(x) = x2 + 5
This function comes from the basic function f(x) = x2 with the constant 5 added to the outside. This gives the basic function a vertical shift UP 5 units.
