Answer:
no Solution
Step-by-step explanation:
-12x-12y=4\\ 3x+3y=0
12x-12y=4
add 12y to both sides
12x-12y+12y=4+12y
divid both sides by -12
\frac{-12x}{-12}=\frac{4}{-12}+\frac{12y}{-12}
simplfy
x=-\frac{1+3y}{3}
\mathrm{Substitute\:}x=-\frac{1+3y}{3}
\begin{bmatrix}3\left(-\frac{1+3y}{3}\right)+3y=0\end{bmatrix}
\begin{bmatrix}-1=0\end{bmatrix}
Answer:
Is important to remember that the reflection of the point (a,b) across the y-axis is the point (-a,b).
Our original equation is 
And after the reflection respect x we got:

Step-by-step explanation:
Is important to remember that the reflection of the point (a,b) across the y-axis is the point (-a,b).
Our original equation is 
And after the reflection respect x we got:

It is 10 more in the thousands than the hundreds... multiply 100 x 10...
Answer:
2x+3(10+x)
Step-by-step explanation:
I'm not sure but I think this might be the answer
Answer:


Step-by-step explanation:
One is given the following function:

One is asked to evaluate the function for
, substitute
in place of
, and simplify to evaluate:



A recursive formula is another method used to represent the formula of a sequence such that each term is expressed as a function of the last term in the sequence. In this case, one is asked to find the recursive formula of an arithmetic sequence: that is, a sequence of numbers where the difference between any two consecutive terms is constant. The following general formula is used to represent the recursive formula of an arithmetic sequence:

Where (
) is the evaluator term (
) represents the term before the evaluator term, and (d) represents the common difference (the result attained from subtracting two consecutive terms). In this case (and in the case for most arithmetic sequences), the common difference can be found in the standard formula of the function. It is the coefficient of the variable (n) or the input variable. Substitute this into the recursive formula, then rewrite the recursive formula such that it suits the needs of the given problem,


