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kondor19780726 [428]
3 years ago
5

The orchestra at millard middle school has 120 members,Of these,30% are eighth-grades students.Find the number of 6th and 7th gr

ade students in the orchestra.
s
Mathematics
1 answer:
vitfil [10]3 years ago
5 0

Answer:

84

Step-by-step explanation:

Well lets begin by noting that 30% are Grade Eight. That means that 70% will be Grade Six and Seven, but thats not the question, the question is how many people are sixth and seventh grade. As I said before the answer is 84. To find 10% of 120, you shift the decimal point one place to the left and get 12. I earlier said 70% are grade six and seven meaning 70/10=7

All thats left is a simple multiplication problem, 12x7 which gives you 84. To ensure you are correct. 84/7=12 and that promises you a correct answer.

If you do not understand the math I did here reply and I will further explain. For now I hope this helps!

Brainly?

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you want to go on an “Around the world cruise” two travel agents are offering cruise packages for $20,000. the agents have unusu
Valentin [98]

Answer:

theyre both the same rate.

Step-by-step explanation:

12months at 1% turns into 12% a year

7 0
3 years ago
A student is selecting 5 different geography books, 4 different chemistry books, and one of 7 different science books. In how ma
malfutka [58]

There would be 5184 ways in which each subject books can be selected.

<u>Explanation:</u>

Number of geography books = 5

Number of chemistry books = 4

Number of Science books = 7

Different ways of selecting geography books = 5!

                                                                            = 5 X 4 X 3 X 2 X 1

                                                                            = 120

Different ways of selecting chemistry books = 4!

                                                                          = 4 X 3 X 2 X 1

                                                                          = 24

Different ways of selecting Science books = 7!

                                                                       = 7 X 6 X 5 X 4 X 3 X 2 X 1

                                                                       = 5040

Total different possible ways they can select them = 120 + 24 + 5040

                                                                                     = 5184

5 0
3 years ago
If you could please help, what is the missing answer?<br><br> Thank you to anyone who helps out!
ICE Princess25 [194]

Answer:

48

Step-by-step explanation:

let s be the snowman, g be the girl, and t be the christmas tree

2s+g=24

2t+2ts=132

3t+2g=26

subtract 2 times the first equation from the third one to get

3t-4s=-22

from the second equation we can deduce

2t(1+s)=132

t(1+s)=66

t=66/(1+s)

Substitute:

3(66)/(1+s)-4s=-22

3(66)/(1+s)=4s-22

3(66)=(4s-22)(1+s)

3(66)=-18s+4s^2-22

4s^2-18s-220=0

using the quadratic formula, we get s = 10, s = -5.5.

2(10)+g=24

g=4

2t(1+10)=132

2t=12

t=6

So 2s+t*g= 20+6*4=48

you would get a different solution for the negative s, but since snowmen cannot be negative, 48 is the answe.r

8 0
3 years ago
Estimate. 3 × 92 What is This???
ivolga24 [154]
It equals 276 but about 300
6 0
3 years ago
Let a and ß be first quadrant angles with cos(a)=
Finger [1]

Since both α and β are in the first quadrant, we know each of cos(α), sin(α), cos(β), and sin(β) are positive. So when we invoke the Pythagorean identity,

sin²(x) + cos²(x) = 1

we always take the positive square root when solving for either sin(x) or cos(x).

Given that cos(α) = √11/7 and sin(β) = √11/4, we find

sin(α) = √(1 - cos²(α)) = √38/7

cos(β) = √(1 - sin²(β)) = √5/4

Now, recall the sum identity for cosine,

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

It follows that

cos(α + β) = √11/7 × √5/4 - √38/7 × √11/4 = (√55 - √418)/28

7 0
2 years ago
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