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erma4kov [3.2K]
3 years ago
12

A piece of art paper is 1 1/2 inches wide and 4 inches long.What is the area of the paper

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
4 0
The answer is 6 square inches because if you turn 1 and 1/2 into 3/2 you can then turn 4 into 4/1 which also turns to 8/2 so that times 3/2 = 12/2 which turns to 6/1 which is 6

The answer is 6 square inches
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If nine is X percent of 45, what is X percent of 5
antoniya [11.8K]

Answer:

x percent of 5 is 1

Step-by-step explanation:

Nine is x percent of 45

x = 20

20 % of 5 = 1

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3 years ago
The two right triangles below are similar what is x the missing side length in triangle DEF
sasho [114]
I think that the answer is C. 10
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3 years ago
SOMEONE HELPPPPPPPPP!!!!!!
Finger [1]

Answer:

104 yd^2.

Step-by-step explanation:

Area of the 2 circles = 2 * π r^2

=  2 * π * 4^2

= 32 π yd^2.

Area of the side of the cylinder = 2 π r h

= 2  π * 4 * 9

= 72 π yd^2.

Total surface area = 32 + 72

= 104 yd^2.

6 0
3 years ago
Read 2 more answers
NO LINKS!!
dexar [7]

Answer: Anything between 0 and 10, excluding both endpoints.

In terms of symbols we can say 0 < w < 10 where w is the width.

===================================================

Explanation:

You could do this with two variables, but I think it's easier to instead use one variable only. This is because the length is dependent on what you pick for the width.

w = width

2w = twice the width

2w-5 = five less than twice the width = length

So,

  • width = w
  • length = 2w-5

which lead to

area = length*width

area = (2w-5)*w

area = 2w^2-5w

area < 150

2w^2 - 5w < 150

2w^2 - 5w - 150 < 0

To solve this inequality, we will solve the equation 2w^2-5w-150 = 0

Use the quadratic formula. Plug in a = 2, b = -5, c = -150

w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\w = \frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-150)}}{2(2)}\\\\w = \frac{5\pm\sqrt{1225}}{4}\\\\w = \frac{5\pm35}{4}\\\\w = \frac{5+35}{4} \ \text{ or } \ w = \frac{5-35}{4}\\\\w = \frac{40}{4} \ \text{ or } \ w = \frac{-30}{4}\\\\w = 10 \ \text{ or } \ w = -7.5\\\\

Ignore the negative solution as it makes no sense to have a negative width.

The only practical root is w = 10.

If w = 10 feet, then the area = 2w^2-5w results in 150 square feet.

----------------------

Based on that root, we need to try a sample value that is to the left of it.

Let's say we try w = 5.

2w^2 - 5w < 150

2*5^2 - 5*5 < 150

25 < 150 ... which is true

This shows that if 0 < w < 10, then 2w^2-5w < 150 is true.

Now try something to the right of 10. I'll pick w = 15

2w^2 - 5w < 150

2*15^2 - 5*15 < 150

375 < 150 ... which is false

It means w > 10 leads to 2w^2-5w < 150  being false.

Therefore w > 10 isn't allowed if we want 2w^2-5w < 150 to be true.

4 0
2 years ago
in order to pass this years math class miriam needs to get at least an 82% write an inequality that shows the scores Miriam coul
xeze [42]
X>-82%.................
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3 years ago
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