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elixir [45]
4 years ago
11

Michael is competing in the long jump event. When he approaches the long jump pit, he jumps with an initial vertical velocity of

40 ft/s. How long is Michael in the air?
A. 2 s

B. 2.5 s

C. 3 s

D. 3.5 s
Mathematics
1 answer:
ddd [48]4 years ago
5 0

Correct answer is D 3.5 s

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An airplane flying at a velocity of 610 m/s lands and comes to a complete stop
Len [333]

A) The airplane slowed down. It states that the plane lands and come to a complete stop over a 53 second period.

B) It decelerates. The speed doesn't increase. It slows down.

C) The answer should be positive. Although the deceleration is slowing down the plane, it's not going at a negative speed.

D) The answer is 11.5m/s. I divided the velocity by the amount of seconds it takes to make a complete stop.

3 0
4 years ago
What are the names of three collinear points?
babymother [125]

Answer:

Hey mate....

Step-by-step explanation:

This is ur answer.....

<h3> <em>Points L, J, and K are collinear.</em></h3>

Hope it helps you,

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3 0
3 years ago
The number of a checking account is also known as a.account number b.checking number c. Bank number d.routing number
Sophie [7]

Answer:

A account number


Step-by-step explanation:


8 0
3 years ago
Pls help me answer this !!
krek1111 [17]

We want our exponential function to look like

y = ab^x.

Let a = the initial y-value.

Our initial value is the first number given for f(x). So, a = 3.

Let b = the number that is needed to go from 3 to 6 to 12 to 24 to 48.

We find b by division.

So, b = the next number divided by the previous.

So, b = 6/3 = 2.

We now plug in our values into the general formula above.

y = ab^x

Answer: y = (3)(2)^x

4 0
3 years ago
A) The sixth term of an AP is twice the 3rd term and the first term is 3. Find the common
dangina [55]

Answer:

Step-by-step explanation:

The nth term of an AP is expressed as;

Tn = a+(n-1)d

a is the first term

n is the number of terms

d is the common difference

Sixth term

T6 = a+(6-1)d

T6 = a+5d

Third term;

T3 = a+(3-1)d

T3 = a+2d

If the sixth term of an AP is twice the 3rd term, then

a+5d = 2(a+2d)

a+5d = 2a+4d

Given a = 3

3+5d = 2(3)+4d

5d-4d = 6-3

d = 3

Common difference is 3

For the 10th term

T10 = a+9d

T10 = 3+9(3)

T10 = 3+27

T10 = 30

Hence the tenth term is 30

7 0
3 years ago
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