What are the names of three collinear points?
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<h3>Answer:</h3>
g(x) = (11/12)x³ +(11/2)x² +(55/12)x -11
<h3>Step-by-step explanation:</h3>A polynomial with zero "a" will have (x -a) as a factor. Your 3rd-degree polynomial will have the three factors ...
... f(x) = (x -(-4))·(x -(-3))·(x -1)
This will have a y-intercept of (4·3·(-1)) = -12. In order to move it to -11, we need to vertically scale this function by a factor of 11/12. Then our poynomial is ...
... g(x) = (11/12)(x+4)(x+3)(x-1)
Multiplying this out, you get ...
... g(x) = (11/12)x³ +(11/2)x² +(55/12)x -11