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4 years ago

How is subtracting like fractions similar to adding like fractions

2 answers:

8 0

Well,

Adding and subtracting like fractions are similar in that both cases simply require you to add the numerators. This is opposed to adding and subtracting non-like fractions because you have to convert them into like fractions.

Sholpan [36]4 years ago

3 0

Because they both have the same rule. They have to have the same denominator.

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Evaluate –3² + (2 – 6)(10).

Nimfa-mama [501]

Answer:

-49

Step-by-step explanation:

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3 years ago

Hallie is estimating the height of the superman rollercoaster in Mitchellville, Maryland.

Nostrana [21]

Answer:

Step-by-step explanation:

5 0

4 years ago

Give your answer in terms of <img src="https://tex.z-dn.net/?f=%5Cpi%20%5C%5C" id="TexFormula1" title="\pi \\" alt="\pi \\" alig

Marina CMI [18]

The length of the band in terms of π is given by the expression:

L = 40mm + π*10mm

<h3>How to get the length of the band?</h3>

Remember that for a circle of diameter D, the circumference is:

C = π*D.

Now, if you look at the image, you can see that the length of the band will be equal to 4 times the diameter of the pencils (one time for each side). Plus 4 times one-fourth of the circumference of each pencil (for the four corners).

because the diameter is 10mm, the length of the band will be:

L = 4*10mm + 4*(π*10mm/4)

L = 40mm + π*10mm

This is the length of the band in terms of π.

If you want to learn more about circles:

brainly.com/question/14283575

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7 0

2 years ago

The degree of the polynomial: 4x²y + x2 - 2y2 is

julsineya [31]

Answer:

2nd degree.

Step-by-step explanation:

The degree is the highest exponent of a polynomial. Therefore, since the only term with an exponent is 4x²y, the degree is 2.

5 0

3 years ago

If y-3x=9, 7x+y=25, what is the value of x and y?

lianna [129]

$\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?$

$\bold{\rm{Solution}} \text{: We'll solve this by substitution method}$

$\dashrightarrow y - 3x = 9 \\ \\ \dashrightarrow \boxed{y = 9 + 3x } \qquad .. \sf eq(1)$

$\text{we got the value of y now getting the value of x}$

$\looparrowright 7x + y = 25 \\ \\ \looparrowright 7x = 25 - y \\ \\ \looparrowright \boxed{x = \frac{25 - y}{7}} \qquad .. \sf eq(2)$

$\text{Now, putting y = 9 + 3x in eq(2)}$

$\hookrightarrow x = \frac{25 - y}{7} \\ \\ \hookrightarrow x = \frac{25 - 9 + 3x}{7} \\ \\ \hookrightarrow 7x = 25 - 9 + 3x \\ \\ \hookrightarrow 7x - 3x = 16 \\ \\ \hookrightarrow 4x = 16 \\ \\ \hookrightarrow x = \frac{16}{4} \\ \\ \star \quad \boxed{ \green{ \frak{ x = 4}}}$

$\text{Now we know the value of x, for getting y we need to put x in eq(1)}$

$: \implies y = 9 + 3x \\ \\ : \implies y = 9 + 3(4) \\ \\ : \implies y = 9 + 12 \\ \\ \star \quad \boxed{\frak{ \green{y = 21}}}$

$\text{Hence, values of x and y are} \: \frak{ \green{4}} \: \text{and} \: \frak{ \green{21}} \: \text{respectively}.$

4 0

3 years ago