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andreev551 [17]
2 years ago
11

Use definition of the derivatives to find the derivative of each function with respect to x.

Mathematics
1 answer:
yanalaym [24]2 years ago
6 0
Answer:
The slope is 5
Step-by-step explanation:
This equation is in slope intercept form
y = mx +b
where m is the slope and b is the y intercept
y = 5x+4
where 5 is the slope and 4 is the y intercept
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Determine whether the point (1, 1) is a solution to the system of equations. Explain your reasoning in complete sentences. graph
erastova [34]
The solutions to system of equations are the point of intersection of the graphs of the equations.
The point of intersection of the graphs of the given equation is (0, 2). Therefore, point (1, 1) is not a solution to the system of equation.
6 0
3 years ago
For the equation below, x is the input and y is the output. y = -4x + 3 If the input is -8, then the output is
KonstantinChe [14]

Answer:

35

Step-by-step explanation:

If is given the value -8 as it is the input then -->

y = -4(-8) + 3

Negative four times negative 8 is positive 32 so

y= 32 + 3

And 32 plus 3 is 35


7 0
3 years ago
Read 2 more answers
​6 2/3÷1/5 juuuuuuuuuuuuuuu
MAXImum [283]

Answer:

Exact Form:

100/3

Decimal Form:

33.3

Mixed Number Form:

33 1/3

<em><u>i hope this helped at all.</u></em>

7 0
2 years ago
Find all possible values of α+
const2013 [10]

Answer:

\rm\displaystyle  0,\pm\pi

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when <u>tanα+tanβ+tanγ = tanαtanβtanγ</u><u> </u>to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =  \tan( \alpha )  \tan( \beta )  \tan( \gamma )  -  \tan( \gamma )

factor out tanγ:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =   \tan( \gamma ) (\tan( \alpha )  \tan( \beta ) -  1)

divide both sides by tanαtanβ-1 and that yields:

\rm\displaystyle   \tan( \gamma ) =  \frac{ \tan( \alpha )  +  \tan( \beta ) }{ \tan( \alpha )  \tan( \beta )    - 1}

multiply both numerator and denominator by-1 which yields:

\rm\displaystyle   \tan( \gamma ) =   -  \bigg(\frac{ \tan( \alpha )  +  \tan( \beta ) }{ 1 - \tan( \alpha )  \tan( \beta )   } \bigg)

recall angle sum indentity of tan:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( \alpha  +  \beta )

let α+β be t and transform:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( t)

remember that tan(t)=tan(t±kπ) so

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta\pm k\pi )

therefore <u>when</u><u> </u><u>k </u><u>is </u><u>1</u> we obtain:

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta\pm \pi )

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

\rm\displaystyle   \tan( \gamma ) =    \tan(   -\alpha  -\beta\pm \pi )

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

\rm\displaystyle  \gamma  =      -   \alpha   -  \beta \pm \pi

isolate -α-β to left hand side and change its sign:

\rm\displaystyle \alpha  +  \beta  +   \gamma  =  \boxed{ \pm \pi  }

<u>when</u><u> </u><u>i</u><u>s</u><u> </u><u>0</u>:

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta \pm 0 )

likewise by Opposite Angle Identity we obtain:

\rm\displaystyle   \tan( \gamma ) =    \tan(   -\alpha   -\beta\pm 0 )

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

\rm\displaystyle  \gamma  =      -   \alpha   -  \beta \pm 0

isolate -α-β to left hand side and change its sign:

\rm\displaystyle \alpha  +  \beta  +   \gamma  =  \boxed{ 0  }

and we're done!

8 0
3 years ago
Read 2 more answers
Your social media ad costs $2.50 per thousand impressions. You get 3.14 million impressions. What is your approximate bill?
melomori [17]

Answer:

7,850

Step-by-step explanation:

7 0
2 years ago
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