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Serga [27]
3 years ago
13

A rectangular field is 400 meters long and 300 meters wide area in square kilometers

Mathematics
1 answer:
Dimas [21]3 years ago
6 0

Answer:

120 kilometers (km^{2})

Step-by-step explanation:

first find the area in meters:

400*300 = 120000

now convert from meters to kilometers

1000 meters = 1 kilometer, therefore:

120000/1000

Simplify

120 kilometers (km^{2})

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If two positive angles have a sum of 180 degrees, they are called supplementary angles. 
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Please help me with this<br><br> 10x(3xy)
sineoko [7]

Answer:

Step-by-step explanation:

10x(3xy)

10*3*x*x*y

30x²y

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3 years ago
A. Y=-1/2x+2<br> B. Y=1/2x+2<br> C. Y=-2x-3<br> D. Y=2x-6
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Answer:

B: Y=1/2×+2 I think that's it

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2 years ago
Can 12,18,30 be a right triangle
ASHA 777 [7]

Answer:

no

Step-by-step explanation:

A set of three integers that can be the lengths of the sides of a right triangle is called a Pythagorean triple. The simplest Pythagorean triple is the set “3, 4, 5.” These numbers are the lengths of the sides of a “3-4-5” Pythagorean right triangle. The list below contains all of the Pythagorean triples in which no number is greater than 50.

3, 4, 5

5, 12, 13 6, 8, 10

7, 24, 25 8, 15, 17 9, 12, 15 9, 40, 41 10, 24, 26 12, 16, 20 12, 35, 37

14, 48, 50 15, 20, 25 15, 36, 39 16, 30, 34 18, 24, 30 20, 21, 29 21, 28, 35 24, 32, 40 27, 36, 45 30, 40, 50

Example Problems

Find the length of the missing side.

13 25 x7

12 x

From the list above, the missing From the list above, the missing side is “5” side is “24”

Show why the set “6,8,10” is a Pythagorean triple.

c2 = a2 + b2 102 =82 +62 100 = 64 + 36 100 = 100

Since the Pythagorean equation is satisfied, the set “6,8,10” is a Pythagorean triple.

7 0
3 years ago
Read 2 more answers
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

P(2)=P(-1)              ...(i)

Substituting x=-1 in the given polynomial.

P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

P(2)=2(8)+m(4)+2n+c

P(2)=16+4m+2n+c

Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

18+3m+3n=0

3m+3n=-18

Divide both sides by 3.

\dfrac{3m+3n}{3}=\dfrac{-18}{3}

m+n=-6

Hence proved.

7 0
3 years ago
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