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3 years ago

Ms.Drevis's garden has lots of apple trees.120 apples fall on ground in 30 seconds.How many apples fall in one second?

Mathematics

1 answer:

aleksley [76]3 years ago

6 0

Answer:

4 apples fall in one second

Step-by-step explanation:

120/30 = 4

120 = the amount of apples

30 = the time in seconds

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Hi I also need help with this please and thank you

OverLord2011 [107]

Answer:

Step-by-step explanation:

y=mx+b where m=slope and b=y intercept

m=(y2-y1)/(x2-x1)

m=(-2-4)/(2+1)

m=-2 so far we have the slope

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-2=-2(2)+b

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Keith_Richards [23]

Answer:

es 29.5?

Step-by-step explanation:

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3 years ago

What is the sum of the zeros of the function: y= x^2 - 5x + 6?

yawa3891 [41]

Answer:

Step-by-step explanation:

The zeros are the values of x for which y = 0

Quadratic formula

x = [5 ± √(5² – 4·1·6)] / [2·1]

= [5 ± √1] / 2

= [5 ± 1] /2

= 2, 3

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3 years ago

The price of a radio was $20 it's on sale for $15 what is the percent of change in the price of a radio

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3 years ago

Read 2 more answers

A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0

3 years ago