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marshall27 [118]
3 years ago
8

Joanna went school supply shopping. She spent $32.49 on notebooks and pencils. Notebooks cost $2.41 each and pencils cost $1.46

each. She bought a total of 19 notebooks and pencils. How many of each did she buy?
Mathematics
1 answer:
Maslowich3 years ago
7 0
Well, you need write the system of equation:

If we call "P" to quantity of pencils and we call "N" to quantity of notebooks, the total quantity of articles in an equation is:

P+N=19

And the total money that Joanna spent in an equation is:

$1.46*P+$2.41*N=$32.49

Now you only need to solve that system.
Good luck!
M.
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max2010maxim [7]

Answer:p = -1.25

Step-by-step explanation:

Simplifying

3 + 17p = -32 + -11p

Solving

3 + 17p = -32 + -11p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '11p' to each side of the equation.

3 + 17p + 11p = -32 + -11p + 11p

Combine like terms: 17p + 11p = 28p

3 + 28p = -32 + -11p + 11p

Combine like terms: -11p + 11p = 0

3 + 28p = -32 + 0

3 + 28p = -32

Add '-3' to each side of the equation.

3 + -3 + 28p = -32 + -3

Combine like terms: 3 + -3 = 0

0 + 28p = -32 + -3

28p = -32 + -3

Combine like terms: -32 + -3 = -35

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p = -1.25

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p = -1.25

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What is the equation of the line that passes through the point (-5,-2) and has a slope of -6/5
tatyana61 [14]

Answer:

The answer is

<h2>y =  -  \frac{6}{5} x - 8  \\</h2>

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

y -  y_1 = m(x -  x_1) \\

where

m is the slope

( x1 , y1) is the point

From the question the point is (-5,-2) and the slope is - 6/5

The equation of the line is

y + 2 =  -  \frac{6}{5} (x + 5) \\ y + 2  =  -  \frac{6}{5} x - 6 \\ y =  -  \frac{6}{5} x - 6 - 2

We have the final answer as

y =  -  \frac{6}{5} x - 8  \\

Hope this helps you

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4 years ago
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olga nikolaevna [1]

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Step-by-step explanation:

Hope it helps :D

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2 years ago
The minimum/maximum value of the function y = a(x − 2)(x − 1) occurs at x = d, what is the value of d?
daser333 [38]

Answer:

d=\frac{3}{2}=1.5

Step-by-step explanation:

We have the function:

y=a(x-2)(x-1)

And we want to find x=d for which the minimum/maximum value will occur.

Notice that our function is a quadratic in factored form.

Remember that the minimum/maximum value always occurs at the vertex point.

And remember that the x-coordinate of the vertex is the axis of symmetry.

Since a quadratic is always symmetrical on both sides of its axis of symmetry, a quadratic’s axis of symmetry is the average of the two roots/zeros of the quadratic.

Therefore, the value x=d such that it produces the minimum/maximum value is the average of the two roots.

Our factors are <em>(x-2) </em>and <em>(x-1)</em>.

Therefore, our roots/zeros are <em>x=1, 2</em>.

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Therefore, regardless of the value of <em>a</em>, the minimum/maximum value will occur at <em>x=d=1.5</em>.

Alternative Method:

Of course, we can also expand to confirm our answer. So:

y=a(x^2-2x-x+2)\\y=a(x^2-3x+2)\\y=ax^2-3ax+2a

The x-coordinate of the vertex is still going to be the place where the minimum/maximum is going to occur.

And the formula for the vertex is:

x=-\frac{b}{2a}

So, we will substitute <em>-3a</em> for <em>b</em> and <em>a</em> for <em>a</em>. This yields:

x=-\frac{-3a}{2a}=\frac{3}{2}=1.5

Confirming our answer.

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