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bekas [8.4K]
3 years ago
14

PLEASE PLEASE HELP

Mathematics
2 answers:
Sophie [7]3 years ago
8 0

my friend she can help u

UNO [17]3 years ago
3 0

Answer:

First we want to calculate the volume of the rectangular prism and subtract it from the triangular prism.

Volume of Rectangular Prism:

Let V1 be the volume of the rectangular prism.

V1 = base * height * length.

The base and the height are both 1.7, but the length is the same length of the triangular prism, which is 4. Thus:

V1 = 1.7 X 1.7 X 4

V1 = 11.56 cubic units

Volume of Triangular Prism:

Let V2 be the volume of the triangular prism:

V2 = (base X height X length) / 2

V2 = (5 X 5.7 X 4)/2

V2 = 57 cubic units.

Now we find the total volume. Let Vt be the total volume. The total volume is the shaded minus the unshaded. Thus:

Vt = V2 - V1

Vt = 57 cubic units - 11.56 cubic units

Vt = 45. 44 cubic units

Therefore the volume of the shaded region is 45.44 cubic units.

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leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

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4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

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