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bekas [8.4K]
3 years ago
14

PLEASE PLEASE HELP

Mathematics
2 answers:
Sophie [7]3 years ago
8 0

my friend she can help u

UNO [17]3 years ago
3 0

Answer:

First we want to calculate the volume of the rectangular prism and subtract it from the triangular prism.

Volume of Rectangular Prism:

Let V1 be the volume of the rectangular prism.

V1 = base * height * length.

The base and the height are both 1.7, but the length is the same length of the triangular prism, which is 4. Thus:

V1 = 1.7 X 1.7 X 4

V1 = 11.56 cubic units

Volume of Triangular Prism:

Let V2 be the volume of the triangular prism:

V2 = (base X height X length) / 2

V2 = (5 X 5.7 X 4)/2

V2 = 57 cubic units.

Now we find the total volume. Let Vt be the total volume. The total volume is the shaded minus the unshaded. Thus:

Vt = V2 - V1

Vt = 57 cubic units - 11.56 cubic units

Vt = 45. 44 cubic units

Therefore the volume of the shaded region is 45.44 cubic units.

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Read 2 more answers
(CO6) From a random sample of 68 businesses, it is found that the mean time that employees spend on personal issues each week is
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Answer:

(1) (4.82, 4.98)

(2) Large sample size

(3) Yes, the temperature is within the confidence interval of (37.40, 37.60)

(4) (15.083, 15.117)

Step-by-step explanation:

Confidence Interval (CI) = mean + or - (t×sd)/√n

(1) mean = 4.9, sd = 0.35, n = 68, degree of freedom = n-1 = 68 - 1 = 67

t-value corresponding to 67 degrees of freedom and 95% confidence level is 1.9958

CI = 4.9 + (1.9958×0.35)/√68 = 4.98

CI = 4.9 - (1.9958×0.35)/√68 = 4.82

CI is (4.82, 4.98)

(2) Error margin = (t-value × standard deviation)/√sample size

From the formula above, error margin varies inversely as the square root of the sample size. Since the relationship between the error margin and sample size is inverse, increase in one (sample size) will conversely lead to a decrease in the other (error margin)

(3) mean = 37.5, sd = 0.6, n= 100, degree of freedom = n-1 = 100-1 = 99

t-value corresponding to 99 degrees of freedom and 90% confidence level is 1.6602

CI = 37.5 + (1.6602×0.6)/√100 = 37.5 + 0.10 = 37.60

CI = 37.5 - (1.6602×0.6)/√100 = 37.5 - 0.10 = 37.40

37.53 is within the confidence interval (37.40, 37.60)

(4) mean = 15.10, sd =0.08, n = 104, degree of freedom = n-1 = 104-1 = 103

t-value corresponding to 103 degrees of freedom and 97% confidence interval is 2.2006

CI = 15.10 + (2.2006×0.08)/√104 = 15.10 + 0.017 = 15.117

CI = 15.10 - (2.2006×0.08)/√104 = 15.10 - 0.017 = 15.083

CI is (15.083, 15.117)

4 0
3 years ago
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