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garik1379 [7]
3 years ago
12

Plz help!!!!!!!!!!!!!

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
5 0

Answer: 5-13i

Step-by-step explanation:

Reika [66]3 years ago
3 0

Answer:

C) 5 - 13i

Step-by-step explanation:

The parentheses don't matter because it is addition. (I think it is the addition associative postulate)

So, we have: <em>8 - 15i + -3 + 2i</em>.

Then, we combine like terms: 8 - 3 = <em>5</em>, -15i + 2i = <em>-13i</em>.

Putting those two values gives us 5 - 13i.

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Y=2x+3 <br> y=3x+1 <br> solve the system of equations using substitution
Lynna [10]

Answer:

(2, 7 )

Step-by-step explanation:

Given the 2 equations

y = 2x + 3 → (1)

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Substitute y = 3x + 1 into (1)

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x = 2

Substitute x = 2 into either of the 2 equations for corresponding value of y

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4 0
3 years ago
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Y^2 +5y+4= ???????????????
joja [24]

Answer:

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4 0
3 years ago
The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum? ​
VLD [36.1K]

Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that

<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>

<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>

where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.

Then the sum is

<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>

and its magnitude is

||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

… = √20 = 2√5

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3 years ago
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5/12 and 3/8 is the answer
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