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nataly862011 [7]
4 years ago
11

Write the following decimals as fractions. a. .76 b. .3 c. .262 d. .8053

Mathematics
2 answers:
natita [175]4 years ago
8 0
A. 19/25 b. 3/10 c. 131/500 d. 8053/10000
vampirchik [111]4 years ago
6 0

Answer: The required fractions are :

(a) \dfrac{19}{25}.

(b) \dfrac{3}{10}.

(c) \dfrac{131}{500}.

(d)  \dfrac{8053}{10000}.

Step-by-step explanation:  We are given to express the following decimals as fractions :

<u><em> (a) : 0.76.</em></u>

Here, since there are two digits after the decimal, so the fraction form is

0.76=\dfrac{76}{100}=\dfrac{19}{25}.

Thus, the required fraction is \dfrac{19}{25}.

<u><em> (b) : 0.3</em></u>

Here, since there is one digit after the decimal, so the required fraction form is

0.3=\dfrac{3}{10}.

Thus, the required fraction is \dfrac{3}{10}.

<u><em> (c) : 0.262</em></u>

Here, since there are three digits after the decimal, so the required fraction form is

0.262=\dfrac{262}{1000}=\dfrac{131}{500}.

Thus, the required fraction is \dfrac{131}{500}.

<u><em> (d) : 0.8053</em></u>

Here, since there are four digits after the decimal, so the required fraction form is

0.8053=\dfrac{8053}{10000}.

Thus, the required fraction is \dfrac{8053}{10000}.

The required fractions are :

(a) \dfrac{19}{25}.

(b) \dfrac{3}{10}.

(c) \dfrac{131}{500}.

(d)  \dfrac{8053}{10000}.

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Two triangles are proportional, and the first triangle has a base of 10 cm and a height of 15 cm. If the base of the second tria
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The length of a rectangle is 2 times the width. The area is 200 square centimeters. Find the length and width of the rectangle
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3 0
3 years ago
Jessica lived in Spain and Colombia for a total of 18 months in order to learn Spanish.She learned an average of 160 words per m
Whitepunk [10]

Answer:

Jessica lived 10 months in Spain and 8 months in Colombia.

Step-by-step explanation:

Let x be the months Jessica spent in Spain, and y the months she spent in Colombia:

   1. x + y = 18

Using the information of words per month learned in each country, we can also write the equation:

    2. 160 * x + 200 * y = 3200

So now we have a system of <u>two equations and two unknowns</u>.

First we <u>express y in terms of x, in the first equation</u>:

  • x + y = 18
  • y = 18 - x

We <u>replace y in the second equation</u>:

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And <u>solve for x</u>:

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Finally we <u>use that value of x in the first equation and solve for y</u>:

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Jessica lived 10 months in Spain and 8 months in Colombia.

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3 years ago
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