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Paraphin [41]
3 years ago
10

How do you find the surface area of this prism?

Mathematics
1 answer:
Vlad1618 [11]3 years ago
8 0
Length * width* height
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Please someone help me with this
shtirl [24]

Answer:

2,-1.5

Step-by-step explanation:

To find the midpoint of a line segment, take the average of the x coordinates and y coordinates of the two points that make it up.

\frac{2+2}{2} ,\frac{4+(-7)}{2}

=\frac{4}{2} , \frac{-3}{2}\frac{4}{2} , \frac{-3}{2}

=2,-1.5

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3 years ago
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What is 576 divided into 4
vesna_86 [32]

Answer:

144

Step-by-step explanation:


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3 years ago
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After school, Camille had a science club meeting for 1 hour, followed by a choir rehearsal that lasted for 40 minutes. If Camill
Vedmedyk [2.9K]
It would be 3:40 since 1 hour and the 40 minutes add up and the choir is after the meeting
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3 years ago
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4/5 divided by 1/3 plus 1/5 minus 3/5
r-ruslan [8.4K]

Answer:

  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

Step-by-step explanation:

Considering the expression

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

Solution Steps:

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

as

\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}

so

=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}    

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}

join  \frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}

so

=\frac{4}{5\left(-\frac{1}{15}\right)}

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=\frac{4}{-5\cdot \frac{1}{15}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}

=-\frac{4}{5\cdot \frac{1}{15}}

\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}

so

=-\frac{4}{\frac{1}{3}}

\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}

so

=-\frac{12}{1}

\mathrm{Apply\:rule}\:\frac{a}{1}=a

=-12

Therefore

                  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

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Question 6
likoan [24]
The answer is B 20,250 cm
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