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kozerog [31]
3 years ago
14

Find the value of the expression

Mathematics
2 answers:
-BARSIC- [3]3 years ago
7 0
I hope this helps you


11×14×10÷4-19×20


1540/-376

-4,09
givi [52]3 years ago
4 0
Your answer would be 7,320.
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Solve 2x+y=3 x+y=5 in substitution method
Nastasia [14]
2x+y=3
- x+y=5
---------------
x=-2

2(-2)+y=3
y=7

-2+y=5
y=7

(-2,7)
4 0
3 years ago
CAN SOMEONE PLEASE SOLVE AND EXPLAIN THIS FREAKING QUESTION????????????????????????????????????/PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEE
mr Goodwill [35]

Answer:

Step-by-step explanation:

sinx=(opposite side)/(hypotenuse)

There really is no ‘explanation’ as that ratio IS the definition of sin.

7 0
2 years ago
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Given the functions below, find g(5) + h(2).<br> g(x) = 2x - 5<br> h(x) = 4x + 5
Ksju [112]
G(5) = 2(5)-5=5
h(2)=4(2)+5=13

So, g(5)+h(2)=13+5=18.
4 0
1 year ago
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NEED THIS DONE SOON
Sati [7]

65Answer:

we can use sin to find the missing length

Step-by-step explanation:

The ratio states that sin of an angle=opposite/hypotenuse

sin(65)=x/6 since we know the angle and the hypotenuse we need to figure out the opposite side

sin(65)=0.906307...

0.906307=x/6

Multiply 6 on both sides to isolate x

The answer is 5.4378...

Rounded to the hundredth is 5.44

5 0
2 years ago
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were​ born
strojnjashka [21]

Answer:

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 335, \pi = \frac{268}{335} = 0.8

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563

For the percentage:

Multiplying the proportions by 100.

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0
3 years ago
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