Question 9
Given the segment XY with the endpoints X and Y
Given that the ray NM is the segment bisector XY
so
NM divides the segment XY into two equal parts
XM = MY
given
XM = 3x+1
MY = 8x-24
so substituting XM = 3x+1 and MY = 8x-24 in the equation
XM = MY
3x+1 = 8x-24
8x-3x = 1+24
5x = 25
divide both sides by 5
5x/5 = 25/5
x = 5
so the value of x = 5
As the length of the segment XY is:
Length of segment XY = XM + MY
= 3x+1 + 8x-24
= 11x - 23
substituting x = 5
= 11(5) - 23
= 55 - 23
= 32
Therefore,
The length of the segment = 32 units
Question 10)
Given the segment XY with the endpoints X and Y
Given that the line n is the segment bisector XY
so
The line divides the segment XY into two equal parts at M
XM = MY
given
XM = 5x+8
MY = 9x+12
so substituting XM = 5x+8 and MY = 9x+12 in the equation
XM = MY
5x+8 = 9x+12
9x-5x = 8-12
4x = -4
divide both sides by 4
4x/4 = -4/4
x = -1
so the value of x = -1
As the length of the segment XY is:
Length of segment XY = XM + MY
= 5x+8 + 9x+12
= 14x + 20
substituting x = 1
= 14(-1) + 20
= -14+20
= 6
Therefore,
The length of the segment XY = 6 units
Answer:
For c=5 there are not solutions for the compound inequality
Step-by-step explanation:
we know that
In the compound inequality
-----> inequality A
-----> inequality B
The solution of the system of inequalities must satisfy inequality A and must satisfy inequality B
so
If c=5
then
There is no solution that satisfies both inequalities simultaneously.
therefore
For c=5 there are not solutions for the compound inequality
Answer:
x=1
Step-by-step explanation:
3x=4-1
3x=3
x=1
Step-by-step explanation:
A portion of the Quadratic Formula proof is shown. Fill in the missing statement. Statements Reasons x² + x + b 4ac 4a? b? 4a² Find a common denominator on the right side of the equation a 2a X? + b 2a b? =4ac 4a? Add the fractions together on the right side of the equation a b2 - 4ac x+ Rewrite the perfect square trinomial on the left side of the equation as a binomial squared 2a 4a 2 Take the square root of both sides of the equation Vb -4ac x+ b 2a + 4a b - 4ас X + 2a + 4a 4ac + 2a 4a 1o ano 4a
1) Finding the zeros of this function f(x) =x² +3x -18
f(x) = x²+3x-18 <em>Factoring this equation, and rewriting it</em>
<em />
<em>Which two numbers whose sum is equal to 3 and their product is equal to 18?</em>
<em>6 -3 = 3 and 6 *-3 = -18</em>
<em />
<em>So we can rewrite as (x +6) (x-3)</em>
<em> </em>
(x+6)(x-3)=0 <em>Applying the Zero product rule, to find the roots</em>
x+6=0,
x=-6
x-3=0,
x=3
S={3,-6}
2) Setting a table, plugging in the values of x into the factored form: (x-6)(x-3)
x | y |
1 | -14 (1 +6)(1-3) =-14
2 | -8 (2 +6)(2-3) =-8
3 | 0
4 | 10
-5 | -8
-6 | 0
3) Plotting the function:
