Question

Plsss help i don't knwo thai

Answer 1

Question 4: The value of x is 4.5.

Question 5: The value of x is 15.6.

Solution:

Question 4:

The given triangle is a right triangle.

Using trigonometric formulas for a right triangle.

$\sin \theta=\frac{\text { opposite }}{\text { hypotenuse }}$

$\sin C=\frac{AB}{BC}$

$\sin 45^\circ=\frac{x}{6.4}$

$\frac{1}{\sqrt{2} } =\frac{x}{6.4}$

Multiply 6.4 on both sides, we get

$\frac{6.4}{\sqrt{2} }=x$

x = 4.5

The value of x is 4.5.

Question 5:

The given triangle is a right triangle.

Using trigonometric formulas for a right triangle.

$\sin \theta=\frac{\text { opposite }}{\text { hypotenuse }}$

$\sin E=\frac{EF}{DF}$

$\sin 60^\circ=\frac{x}{18}$

$\frac{\sqrt3}{2} =\frac{x}{18}$

Multiply 18 on both sides, we get

x = 15.6

The value of x is 15.6.