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artcher [175]
3 years ago
15

Shawn and Ellie are construction workers. Shawn can complete a concrete job in 4 hours, while Ellie can complete it in 6 hours.

The foreman says that it will take them 5 hours to complete it if they work together. Explain each step in solving this equation, and determine if the foreman is correct or not.
Mathematics
1 answer:
Lorico [155]3 years ago
8 0

shawn does 1 job in 6 hours

 turn that into a fraction 1/6

Ellie 1 in 4 so fraction is 1/4

1/6 + 1/4 = 5/12

12/5 = 2.4

 it will take them 2.4 hours

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Trigonometry question help ,?? (15 points)
Taya2010 [7]
SOH CAH TOA
This is the acronym for all trigonometric ratios. 
Sin. = opposite/hypotenuse
Cos. = adjacent/ hypotenuse
Tan. = opposite/ adjacent.

In this picture the OPPOSITE leg and the HYPOTENUSE is given to us. With this information we can apply the "TOA" ratio.

Sin. R = opposite/hypotenuse
Sin. R = 3/4 or 0.75
Use a calculator or table to find 0.75 in the sin. column.
The final answer should be 49.
Sin. 49 = 0.7547
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4 years ago
PLS PLS PLS I NEED HELP WITH ONLY 3C I HAVE DONE THIS QUESTION TWICE BUT I KEEP GETTING THE WRONG ANSWER PLS PLS HELP ME
AVprozaik [17]
Tan(35)=ck/cd
0.7= ck/3
ck=2.1

Tan(65)=cj/cd
2.1=cj/3
cj=6.3

jk=6.3-2.1=4.2
8 0
3 years ago
What is the instataneous rate of change at x=2 of the function f given by f(x)= x^2-2÷x-1​
Dima020 [189]

Answer:

4.5

Step-by-step explanation:

To find the instantaneous rate of chance, take the derivative:

f(x) =  {x}^{2}  -  \frac{2}{x}  - 1 \\  \frac{d}{dx} f(x) = 2x +  \frac{2}{ {x}^{2} }

Remember to use power rule:

\frac{d}{dx}  {x}^{a}  = a {x}^{a - 1}

To differentiate -2/x, think of it as:

- 2 {x}^{ - 1}

Then, substitute 2 for x:

2(2) +  \frac{2}{ {2}^{2} }  \\ 4 +  \frac{2}{4}  = 4.5

6 0
3 years ago
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Vinvika [58]

it's 1,310

Step-by-step explanation:

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4 0
3 years ago
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Question set 1: One instructor believes that students take more than 2 classes per quarter on average. He randomly interviewed a
Sveta_85 [38]

Answer:

There is statistical evidence at 95% level to claim that students attend more than 2 classes per quarter

Step-by-step explanation:

Given that one instructor believes that students take more than 2 classes per quarter on average. Let X be the no of classes students take.

H_0: \bar x =2\\H_a: \bar x >2

(Right tailed test at 5% significance level)

\bar x =2,3 \\s = 0.8

Mean difference = 2.3-2=0.3

Std error = \frac{0.8}{\sqrt{24} } \\=0.1633

Test statistic t = mean diff/std error = 1.84

p value =0.039

Since p <0.05, we reject null hypothesis.

There is statistical evidence at 95% level to claim that students attend more than 2 classes per quarter

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4 years ago
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