Answer:
C. Basic swimming capability.
Explanation:
one of the way before participating in any water-based sport is know how to do the basic swimming way.
Answer:
The temperature of air in the tire is 55.57 ºC
Explanation:
Please look at the solution in the attached Word file
Answer:
(a) 5142.86 m
(b) 317.5 m/s
(c) 49.3 degree C
Explanation:
m = 100 kg, Q = 1200 kcal = 1200 x 1000 x 4.2 = 504 x 10^4 J
(a) Let the altitude be h
Q = m x g x h
504 x 10^4 = 100 x 9.8 x h
h = 5142.86 m
(b) Let v be the speed
Q = 1/2 m v^2
504 x 10^4 = 1/2 x 100 x v^2
v = 317.5 m/s
(c) The temperature of normal human body, T1 = 37 degree C
Let the final temperature is T2.
Q = m x c x (T2 - T1)
504 x 10^4 = 100 x 4.1 x 1000 x (T2 - 37)
T2 = 49.3 degree C
Answer:
Explanation:
F = ma
a = F/m
a = (200.0 + 150.0 - 100.0) / 91.0
a = 250.0/91.0
a = 2.7472527...
a = 2.75 m/s²
