Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Answer: 1680 inches cubed
Step-by-step explanation:
Volume = Length x Width x Height
V = 20 x 7 x 12
V = 140 x 12
V = 1680 inches cubed
I would think b, but if u don’t agree then I would go with d
D = d + Vt,
d = 1.0 miles,
V = -70 miles per hour,(- because its coming towards you)
And about D
Imagine you're standing at the centre of the street. a car is coming towards you. You can easily see that car will be X miles away from you two times. When Driving towards you And When Driving away from you. So
we have two D. + 0.15 miles and -0.15 miles.
0.15= 1 - 70t
-0.15=1-70t
From here
t equals
either
0.85/70 hours which is 0.85/70*3600 second about 43.7 sec.
or
1.15/70 hours or 1.15*3600/70 about 59 sec.
