What is an equation of the line that passes through the point (2, 4 and is perpendicular to the line whose equation is 3y = 6x 3
?
1 answer:
Perpendicular line always have slopes that are negative reciprocals of one another. Mathematically,
m1*m2=-1
So to be perpendicular to the line given, let's rearrange it to the point slope form of a line...
3y=6x ?3 (not sure what you wanted to type there)
anyway isolating y by dividing both side by three will leave 2x where 2 is the slope.
So for the other line to be perpendicular, m*2=-1, m=-1/2, now we have:
y=-x/2 +b, we can now you the point given to solve for b
4=-2/2 +b
4=-1+b
b=5 so
y=-x/2 +5 or more neatly
y=(10-x)/2
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Answer:
A is correct
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
point-slope equation is y-y1=m(x-x1)
y1=2
x1=6
m=(-5/7)
so the equation is y-2=-5/7(x-6)
hope this helps :3
Step-by-step explanation:
X+3 =2X +1
X= 2
sides,,5,5 ,6 ft
perimeter = 5+5+6 = 16
Answer:
The correct answer to the following question will be Option d (181 degrees of freedom).
Step-by-step explanation:
The given values are:
Regression model,
n = 200
Observations,
p = 18
Now,
⇒ 
On putting the estimated values, we get
⇒ 
⇒ 
So that the correct choice will be "181 degrees of freedom".
