Let be the set of all students in the <u>c</u>lassroom.
Let and
be the sets of students that pass <u>p</u>hysics and <u>m</u>ath, respectively.
We're given
i. We can split up into subsets of students that pass both physics and math
and those that pass only physics
. These sets are disjoint, so
ii. 9 students fails both subjects, so we find
By the inclusion/exclusion principle,
Using the result from part (i), we have
and so the probability of selecting a student from this set is
Answer:
At-most 3 birdhouses.
Step-by-step explanation:
Let B represent the number of birds and H represent the number of birdhouses that Nathaniel can build with his Lego blocks.
We have been given that Nathaniel builds birds and birdhouses using Lego blocks. The inequality represents the number of birds and birdhouses Nathaniel could build.
To find the number of birdhouses that Nathaniel can build after making 50 birds, we will substitute B=50 in our given inequality and then solve for H.
Let us subtract 2150 from both sides of our inequality.
Let us divide both both sides of our inequality by 215.
As Nathaniel can make build less than or equal to 3.953488 and the biggest integer less than or equal to 3.953 is 3, therefore, Nathaniel can build at-most 3 birdhouses with remaining Lego blocks.