<h3>Bubble Inc., a chewing gum advertisement represents the brand's Unique selling proposition.
</h3>
Explanation:
The Unique Selling Proposition, or Unique Selling Point (USP), is a marketing term that refers to any attribute or feature of a product or service that separates it from the competition and emphasizes its specific customer benefits.
Businesses with a unique selling proposition stand for something particular, and it becomes Bubble Inc., known for. A clearly defined USP can be an important tool for helping Bubble Inc., marketing strategies and concentrate them on setting their brand and goods apart from their competition.
Answer:
Insurable interest
Explanation:
The insurance interest is the interest of the insurer while taking the policy so that the risk of the loss is reduced also it is an important requirement that makes the firm or the event to be legal, valid, enforceable, and protected against any harmful acts done intentionally
Therefore according to the given situation, the concept in which enough interest must exist on the part of the insurer while taking the policy is known as the insurer interest
Hence, the first option is correct
The overall capitalization rate by direct market extraction assuming each property is equally comparable to the subject is 11.4%
Explanation:
Capitalization is the accounting of expenditures and the regular distribution of investments in fixed reserves over future years. Capitalisation, in other words, includes an expense usually documented in a temporary account and reported as an income account on a permanent basis.
Take the average of the three property capitalization rates to find the overall capitalization rate.
Answer:
Solution:
A.
p_x=3, G_x=\frac {100}{3}=33\frac{1}{3}p
x
=3,G
x
=
3
100
=33
3
1
p_y=5, G_y=\frac{100}{5}=20p
y
=5,G
y
=
5
100
=20
B.
100-0.25\times 100=75100−0.25×100=75
p_x=3, G_x=\frac {75}{3}=25p
x
=3,G
x
=
3
75
=25
p_y=5, G_y=\frac{75}{5}=15p
y
=5,G
y
=
5
75
=15
C.
p_x=6, G_x=\frac {100}{6}=16\frac{2}{3}p
x
=6,G
x
=
6
100
=16
3
2
D.
p_y=5, G_y=\frac{100}{4}=25p
y
=5,G
y
=
4
100
=25
2.
MU_x=68-60=8, p_x=2MU
x
=68−60=8,p
x
=2
MU_y=29-25=4, p_y-?MU
y
=29−25=4,p
y
−?
\frac {MU_x}{p_x}=\frac{MU_y}{p_y}
p
x
MU
x
=
p
y
MU
y
\frac{8}{2}=\frac {4}{p_y}
2
8
=
p
y
4
p_y=1p
y
=1