14. 1.5, 10 <- Answer
15. 5,1 <- Answer
Proof 14
Solve the following system:
{2 x - y = -7 | (equation 1)
4 x - y = -4 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -4 | (equation 1)
2 x - y = -7 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x - y = -4 | (equation 1)
0 x - y/2 = -5 | (equation 2)
Multiply equation 2 by -2:
{4 x - y = -4 | (equation 1)
0 x+y = 10 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = 6 | (equation 1)
0 x+y = 10 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3/2 | (equation 1)
0 x+y = 10 | (equation 2)
Collect results:
Answer: {x = 1.5
y = 10
Proof 15.
Solve the following system:
{5 x + 7 y = 32 | (equation 1)
8 x + 6 y = 46 | (equation 2)
Swap equation 1 with equation 2:
{8 x + 6 y = 46 | (equation 1)
5 x + 7 y = 32 | (equation 2)
Subtract 5/8 × (equation 1) from equation 2:{8 x + 6 y = 46 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 23 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Multiply equation 2 by 4/13:
{4 x + 3 y = 23 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 20 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 5 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer: {x = 5 y = 1
Answer:
C) 61
Step-by-step explanation:
The answer is D, 14 percent
The shape moved over 10 and up three. Is this what you’re looking for?
![x^5-8x^3-9x\\\\[Factor]x(x+3)(x-3)(x^2+1)\\\\[Set all the items equal to 0.]x = 0\\\\x+3=0\\x=-3\\\\x-3=0\\x=3\\\\x^2 +1=0\\x^2=-1\\x=i,-i](https://tex.z-dn.net/?f=x%5E5-8x%5E3-9x%5C%5C%5C%5C%5BFactor%5Dx%28x%2B3%29%28x-3%29%28x%5E2%2B1%29%5C%5C%5C%5C%5BSet%20all%20the%20items%20equal%20to%200.%5Dx%20%3D%200%5C%5C%5C%5Cx%2B3%3D0%5C%5Cx%3D-3%5C%5C%5C%5Cx-3%3D0%5C%5Cx%3D3%5C%5C%5C%5Cx%5E2%20%2B1%3D0%5C%5Cx%5E2%3D-1%5C%5Cx%3Di%2C-i)
The 5 roots are 0, -3, 3, i, and -i.
⭐ Answered by Hyperrspace (Ace) ⭐
⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐
⭐ If you have questions, leave a comment, I'm happy to help! ⭐