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leonid [27]
4 years ago
10

Simplify: (4x)(-x^2)(5x^3)

Mathematics
2 answers:
Mekhanik [1.2K]4 years ago
5 0

Answer:

-20 x^6

Step-by-step explanation:

(4x)(-x^2)(5x^3)

Multiply the numbers

4*-1 *5 = -20

Add the exponents

x^1 * x^2 * x^3

x^(1+2+3)

x^6

Multiply back together

-20 x^6

Shkiper50 [21]4 years ago
3 0

Answer:

The answer is

<h2>- 20 {x}^{6}</h2>

Step-by-step explanation:

(4x )( - x²)(5x³)

Expand the terms

That's

-4x³( 5x³)

Next multiply the numbers

That's

- 20( x³)(x³)

Using the rules of indices multiply the x's in the expression

That's

<h3>{a}^{x}  \times  {a}^{x}  =  {a}^{y + y}</h3>

So we have

<h3>{x}^{3}  \times  {x}^{3}  =  {x}^{3 + 3}  =  {x}^{6}</h3>

We have the final answer as

<h3>- 20 {x}^{6}</h3>

Hope this helps you

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Please help me with this question​
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4 0
3 years ago
A radio antenna is kept perpendicular to the ground by three wires of equal length. The wires touch the ground at three points o
Elena-2011 [213]

Answer:

The coordinates of the base of the antenna is (-6. 1)

Step-by-step explanation:

Here  we are required to find the center of a circle given points on the circumference

The equation of  a circle is

(x - h)² + (y - k)² = r²

Where:

x and y are points on the circumference

h and k are coordinates of the center of the circle and

r = The radius of the circle

Since we have the values for the points on the circumference, we are left with three unknowns, which we can find with three equations as follows;

By plugging in the values for x and y at the respective points we get,

At (9, -19) → (9 - h)² + (-19 - k)² = r²...............(1)

At (-21, -19) → (-21 - h)² + (-19 - k)² = r².....,...(2)

At (14, 16 ) → (14 - h)² + (16 - k)² = r² ............(3)

Solving, we get  from (1)  (-19 - k)² = r² - (9 - h)²

Plugging in the value of (-19 - k)² in equation (2) we get

(-21 - h)² + r² - (9 - h)² = r²

So that (-21 - h)²  - (9 - h)² = r² -  r² = 0

and   (-21 - h)²  - (9 - h)² = 0 gives

60·h +360 = 0 or h = -6

Plugging in the value of h = -6 in equation (3) we get

(14 - (-6))² + (16 - k)² = r²

20² + (16 - k)² = r² .................(4)

similarly from equation (1) we get

(9 - (-6))² + (-19 - k)² = r²

15² + (-19 - k)² = r²  ................(5)

Subtracting equation (5) from (4) gives

20² - 15² +  (16 - k)² - (-19 - k)² = 0

Which gives

-70·k + 70 = 0

or k = 1

Therefore the coordinates of the base of the antenna = (-6. 1).

6 0
4 years ago
160 marbles fit inside a tin box measuring 4.5 x 4.5 x 7.5 if they are transferred to a tin cylinder that is 4.5 in diameter how
Len [333]
<span>(box volume/ball volume) * packing density = # mables that fit in box max packing density is pi/3*sqrt(2) for spheres, according to the Kepler conjecture, so if ball volume is b, (4.5 * 4.5 * 7.5 / b) * (pi/3*sqrt(2)) = 160 151.875 / b * (pi/3*sqrt(2)) = 160 151.875 * pi / b * 3 * sqrt(2) = 160 50.625 * pi / b * sqrt(2) = 160 10.125 * pi / 32 * sqrt(2) = b b ~ 0.7 For a tin cylinder of 4.5 diameter, the volume is (4.5/2)^2 * pi * h. Using the formula again, (box volume/ball volume) * packing density = # mables (5.0625 * pi * h / (10.125 * pi / 32 * sqrt(2)) * (pi/3*sqrt(2)) = 160 (5.0625 * pi * h * 32 * sqrt(2) / 10.125 * pi) * (pi/3*sqrt(2)) = 160 5.0625 * h * 32 * sqrt(2) / 10.125 * (pi/3*sqrt(2)) = 160 162 * h * sqrt(2) * pi / 10.125 * 3 * sqrt(2) = 160 54 * h * pi / 10.125 = 160 54 * h * pi = 1620 h * pi = 30 h = 30/pi h ~ 9.55 So if the marbles are of equal size, and both the box and cylinder are packed as tightly as possible, the cylinder would have to be 9.55 units tall.</span>
6 0
4 years ago
17-2p=2p+5+2p solve for p
alina1380 [7]
P=2

<span>17-2p=2p+5+2p    P=2

I hope this helps.

Can you make my answer the brainliest please?
</span>
5 0
3 years ago
Read 2 more answers
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