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Crazy boy [7]
3 years ago
11

Prove Euler's identity using Euler's formula. e^ix = cos x + i sin x

Mathematics
1 answer:
Korolek [52]3 years ago
3 0

First list all the terms out.

e^ix = 1 + ix/1! + (ix)^2/2! + (ix)^3/3! ...

Then, we can expand them.

e^ix = 1 + ix/1! + i^2x^2/2! + i^3x^3/3!...

Then, we can use the rules of raising i to a power.

e^ix = 1 + ix - x^2/2! - ix^3/3!...

Then, we can sort all the real and imaginary terms.

e^ix = (1 - x^2/2!...) + i(x - x^3/3!...)

We can simplify this.

e^ix = cos x + i sin x

This is Euler's Formula.

What happens if we put in pi?

x = pi

e^i*pi = cos(pi) + i sin(pi)

cos(pi) = -1

i sin(pi) = 0

e^i*pi = -1 OR e^i*pi + 1 = 0

That is Euler's identity.

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Yvonne bought a car for $10,300. After 3 years, the value of the car was $6,250. The value of this car decreases exponentially o
Likurg_2 [28]

Answer:

A = $44,778.84

A = P + I where

P (principal) = $10,300.00

I (interest) = $34,478.84 or 12 months

Step-by-step explanation:

Given: Yvonne bought a car for $10,300. After 3 years, the value of the car was $6,250. 50%

To find: In approximately what number of additional months will the value of Yvonne’s car be 50% of the price she originally paid?

Formula: (\frac{interest rate}{number of payments}) × loan principal = interest

Solution:  Divide your interest rate by the number of payments you’ll make in the year (interest rates are expressed annually). So, for example, if you’re making monthly payments, divide by 12. Multiply it by the balance of your loan, which for the first payment, will be your whole principal amount.

(This gives you the amount of interest you pay the first month.)

First, convert R as a percent to r as a decimal

r = R/100

r = 50/100

r = 0.5 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

A = 10,300.00(1 + 0.5/12)(12)(3)

A = 10,300.00(1 + 0.041666667)(36)

A = $44,778.84

Henceforth:

The total amount accrued, principal plus interest, with compound interest on a principal of $10,300.00 at a rate of 50% per year compounded 12 times per year over 3 years is $44,778.84.

6 0
2 years ago
Simplify 4x^2+36/4x×1/5x
I am Lyosha [343]

The simplified version of the expression is this: 5(x² + 9) ÷ x.

3 0
3 years ago
The total cost of producing a type of tractor is given by C(x)=11000−20x+0.02x2, where x is the number of tractors produced. How
marissa [1.9K]

Answer:

Step-by-step explanation:

You need to complete the square.

C(x) = 0.02(x^2 - 1000x  ...)  + 11000

C(x) = 0.02 (x^2 - 1000x + 500^2) + 11000 - 5000

C(x) = 0.02 (x^2 - 1000x + 500^2) + 6000

C(x) = 0.02(x - 500)^2 + 6000

Now if you look at the answer you will find that the square is completed. That means that number of tractors you could produce is 500 at a cost of 6000

There is a flow to this question that you may have trouble understanding.

First of all the 500^2. That comes from taking 1/2 of 1000 and squaring it. That's what you need to complete the square.

Bur that is not what you have adding into the equation. Remember that there is a 0.02 in front of the brackets.

500^2 = 250000

0.02 * 250000 = 5000

So that number must be subtracted to make the square = 0. When you remove the brackets, you should get 11000 all in all.

So what you have outside the brackets is 11000 - 5000 = 6000

The rest is just standard for completing the square.

5 0
2 years ago
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