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Crazy boy [7]
3 years ago
11

Prove Euler's identity using Euler's formula. e^ix = cos x + i sin x

Mathematics
1 answer:
Korolek [52]3 years ago
3 0

First list all the terms out.

e^ix = 1 + ix/1! + (ix)^2/2! + (ix)^3/3! ...

Then, we can expand them.

e^ix = 1 + ix/1! + i^2x^2/2! + i^3x^3/3!...

Then, we can use the rules of raising i to a power.

e^ix = 1 + ix - x^2/2! - ix^3/3!...

Then, we can sort all the real and imaginary terms.

e^ix = (1 - x^2/2!...) + i(x - x^3/3!...)

We can simplify this.

e^ix = cos x + i sin x

This is Euler's Formula.

What happens if we put in pi?

x = pi

e^i*pi = cos(pi) + i sin(pi)

cos(pi) = -1

i sin(pi) = 0

e^i*pi = -1 OR e^i*pi + 1 = 0

That is Euler's identity.

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Answer:

x = 3

Step-by-step explanation:

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Now we subtract 14x from each side. This leaves us with:

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Now we need subtract 1 from each side, leaving us with:

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And now we divide each side by 6x, leaving us with.

3 = x.

And if you insert three into both of the equations, it will result in 25.

(Hope this helped!)

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2 years ago
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Replace all occurrences of y with 2x−1 in each equation.

0=0

y=2x−1

Remove any equations from the system that are always true.

y=2x−1

Step-by-step explanation:

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Can someone solve this
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Answer:

f(h(-1)) = -1

Step-by-step explanation:

f(x) = (x-4)/3

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f(h(-1)) = ?

So first off we need to solve for h(-1):

h(x) = 3x + 4

h(-1) = 3(-1) + 4

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Next, we plug this value into the f(x) equation:

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f(h(-1)) may look confusing but it is just f(x) with x being the resulting value for h(-1)

Thus we can say that f(h(-1)) is equal to -1

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