I hope this help you. Good luck
Answer:
The answer to your question is 20x + 21y + 14
Step-by-step explanation:
Data
Expression 1/5 (150x - 80y + 50 - 50x - 25y + 20)
Process
1.- Multiply 1/5 by each term
150/5x - 80/5y + 50/5 - 50/5x - 25/5y + 20/5
2.- Simplify
30x - 16y + 10 - 10x - 5y + 4
3.- Simplify like terms
(30x - 10x) + (-16y - 5y) + (10 + 4)
4.- Result
20x + 21y + 14
Answer:
The answer is a
Step-by-step explanation:
The distance from the near end of the runway to the plane, divided by the altitude is the tangent of (90 degrees minus the angle of depression). Let "d1" be the distance to the near end of the runway, and "d2" be the distance to the far end of the runway. Let "a" be the altitude of the plane.
d1/a = tan(90 - 31)
d1 = a*tan(90 - 31)
d2/a = tan(90 - 23)
d2 = a*tan(90 - 23)
runway length = d2 - d1 = a*(tan(67) - tan(59))
length = 1800*(.6916) = 1245m = 1.2km
the answer is "a"
Answer:
6 pies de distanciamientoya hasta ya casi se vuelve una ley
