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3 years ago

A gift box in the shape of a cube has a volume of 216 cm3 . What is the area of the base of the box

1 answer:

3 0

The volume consists of L*W*H. Since it is a cube, each measurement will be the same. The cube is 6 for Length, width, and height. The SA for the base of the box is 36cm.

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Use synthetic substitution to find f(-2) for f(x) = x^3-6x^2+5x+1

Vesna [10]

(-2)^3 - 6(-2)^2 + 5(-2) + 1
-8 - 24 -10 + 1
-41

5 0

3 years ago

What is the difference of 4.7 and 0.423

Strike441 [17]

The answer would be 4.7-0.423 which equals 4.277

7 0

3 years ago

Read 2 more answers

23 and 24 I need help please

Gnoma [55]

Answer:

They should purchase the snack with the purple box. This is the answer for 23, i don't know what 24 is sorry.

Step-by-step explanation:

24÷3=8

8×5=40

so the first snacks would cost them $40.

then:

24÷4=6

6×6=36

so the second snacks would cost them $36

5 0

4 years ago

1) -3p+6p 2) 7x-x 3) -10v+6v 4) 9+5r-9r 5) 5n+9n Answer all you can!

valentina_108 [34]

1. 3p
2. 6x
3. -4v
4. -4r+9
5. 14n

3 0

3 years ago

Read 2 more answers

Pls help due ASAP.... Pls show workings.

Ann [662]

Answer:

We can conclude that the distance from Sandy's Hotel to Trader Joes' Store is:

d = 8.06 miles

Step-by-step explanation:

From the coordinate plane, we can clearly identify that:

Sandy's Hotel is located at the point (-8, 9)

Trader Joes' Store is located at the point (-4, 2)

The distance from Sandy's Hotel to Trader Joes' Store can be calculated such as:

$d=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

The distance between (-8, 9) and (-4, 2)

$d=\sqrt{\left(-4-\left(-8\right)\right)^2+\left(2-9\right)^2}$

$=\sqrt{\left(-4+8\right)^2+\left(2-9\right)^2}$

$=\sqrt{4^2+7^2}$

$=\sqrt{16+49}$

$=\sqrt{65}$

$=8.06$ miles

Therefore, we can conclude that the distance from Sandy's Hotel to Trader Joes' Store is:

d = 8.06 miles

8 0

3 years ago