Find the area of the combined rectangles

Gigi gets manicures that cost $25 each. Gigi wants to spend no more than $100 on manicures. Which of the following could be used

Ronch [10]

The correct answer is D:)

5 0

3 years ago

N a basketball game, Archie made 3/5 of his shots. Which numbered choice has a value that is the same as the ratio Archie made i

Mamont248 [21]

Basically you want to find an equivalent fraction for 3/5 in the answer choices.

12/20 equals 3/5 because 3/5 x 4/4 (or 1) = 12/20

answer: 4

8 0

3 years ago

Adimas found the mean of her 11 math test scores for the first semester. X = StartFraction (76 87 65 88 67 84 77 82 91 85 90) Ov

Reika [66]

To find the solution we will first find the difference between each number and mean, and then substitute the value in the formula of standard deviation.

The standard deviation is 8.4477 and the variance is 71.40.

Given to us

Test scores of Adimas = (76, 87, 65, 88, 67, 84, 77, 82, 91, 85, 90)
Mean = 81

<h3>Standard Deviation</h3>

difference between each number and mean,

$x_1 -\mu= 76-81 = -5\\
x_2-\mu = 87-81 = 6\\
x_3-\mu = 65-81 = -16\\
x_4-\mu = 88 -81 = 7\\
x_5-\mu = 67-81 = -14\\
x_6 -\mu= 84-81 = 3\\
x_7 -\mu= 77-81 = -4\\
x_8 -\mu= 81-81 = 1\\
x_9 -\mu= 91-81 = 10\\
x_{10}-\mu=85-81 = 4\\
x_{11} -\mu= 90-81 = 9$

$\sum(x-\mu)^2 = x_1^2+x_2^2+x_3^2+x_4^2+x_5^2+x_6^2+x_7^2+x_8^2+x_9^2+x_{10}^2+x_{11}^2$

= 25 + 36 + 256 + 49 + 196 + 9 + 16 + 1 + 100 +16 + 81

= 785

$\rm{ Standard\ Deviation = \sqrt{\dfrac{\sum{(X-\mu)^2}} {n}$

$\sigma= \sqrt{\dfrac{785}{11}}\\\\
\sigma = 8.4477$

<h3>Variance</h3>

Variance = $\sigma ^2$

= 71.40

Hence, the standard deviation is 8.4477 and the variance is 71.40.

Learn more about Standard Deviation:

brainly.com/question/12402189

3 0

2 years ago

How many Solutions does this system have? (1 point)

mixas84 [53]

The given system of equation that is $2x+y=3$ and $6x=9-3y$ has infinite number of solutions.

Option -C.

<u>Solution:</u>

Need to determine number of solution given system of equation has.

$\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}$

Let us first bring the equation in standard form for comparison

$\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}$

$\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$

To check how many solutions are there for system of equations $a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0$ , we need to compare ratios of $\frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}$

In our case,

$a_{1} = 2, b_{1}= 1\text{ and }c_{1}= -3$

$a_{2} = 6, b_{2} = 3,\text{ and }c_{2} = -9$

$\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}$

As $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$ , so given system of equations have infinite number of solutions.

Hence, we can conclude that system has infinite number of solutions.

5 0

3 years ago

For the function g(x)= x-9/x+7, solve the following inequality. g(x)>_0

jasenka [17]

Answer:

$x< -7 ; x\geq9$

Step-by-step explanation:

You start noticing that for x = 9 g(x) =0, and for x= -7 the function isn't defined.

That splits the number lines in 3 areas: x<-7; -7<x<9, and x>9. (notice the strict inequalities since we already discussed the breaking points.

Let's try a point in each interval, namely, since i like the values, -10, 0, 10.

$g(-10) = \frac{-10-9}{-10+7} =\frac{-19}{-3} >0\\g(0) = \frac{0-9}{0+7}=-\frac{9}{7} 0$

We have all the informations we need. The value we need are $x< -7 ; x\geq9$

3 0

2 years ago