The table is missing in the question. The table is provided here :
Group 1 Group 2
34.86 64.14 mean
21.99 20.46 standard deviation
7 7 n
Solution :
a). The IV or independent variable = Group 1
The DV or the dependent variable = Group 2
b).
Therefore, 
t = -2.579143
Now, 
df = 7 - 1
= 6
Therefore the value of p :
= 0.020908803
The p value is 0.0209
So we reject the null hypothesis and conclude that 
Step-by-step explanation:
You can imagine this figure as a rectangle and cube
If you want volume of this irregular figure than you have to do it like this:
V(figure)= V(rectangle)+ V(cube)
V(figure)= a*b*c+ a³
V(figure)= 4*3*(I don't see dimension on the left)+ 3³
V(figure)=12*(I don't see dimension on the left)+ 27
And only you have to to do is to set this dimension which I can't see.
The negative exponents that are in the numerator pass to positive if the base is moved to the denominator, and the negative exponents that are in the denominator pass to positive if the base is moved to the numerator.
The the answer is the option B: xx^4 / y^2 y^6
Answer:
.01%*
Step-by-step explanation:
Individually, they both have a rate of failure of 1%.
.01 x .01 = .0001
Therefore they have a combined probability of failure of .01%
*Disclaimer!!
I am not the best at this area in math so I would still reference against someone else's answer, but this is my best effort :)
