Answer:
Points P ( 4 , - 7 ) and Q ( 1 , 5 ) belong to the equations:
1 ; 4 ; and 5
Step-by-step explanation:
Equations 1 ; 4 and 5 are the same equation
Equation 1 y = - 4*x + 9
Equation 4
y + 7 = - 4 * ( x - 4 ) ⇒ y + 7 = - 4*x + 16 ⇒ y = - 4*x - 7 + 16
y = -4*x + 9
Equation 5
4*x + y = 9 ⇒ y = - 4*x + 9
Now for the equation y = - 4*x + 9
P ( 4 , -7)
For x = 4 y = - 4*(4) + 9 ⇒ y = - 16 + 9 ⇒ y = - 7
Then point P is in the line y = - 4*x + 9
Point Q (1 , 5 )
For x = 1 y = - 4 * ( 1) + 9 ⇒ y = - 4 + 9 ⇒ y = 5
Point Q is in the line y = - 4*x + 9
Equation 2
y = - 4*x - 23
Point P ( 4 , - 7 )
For x = 4 y = 16 - 23 y = - 7
Point P is in the line
Point Q
For x = 1 y = - 4 *(1) - 23 ⇒ y = - 27
Then poin Q is not in the line
Equation 3
y - 1 = - 4 * ( x - 4 )
y - 1 = -4*x + 16 ⇒ y = - 4*x + 17
Point P ( 4 , - 7 )
For x = 4
y = - 16 + 17 ⇒ y = 1
Point P is not in the line
And Point Q ( 1 , 5 )
For x = 1
y = - 4* ( 1 ) + 17 ⇒ y = 13 Q is not in the line
There are an infinite set of values which would work
Isisbwauuqnqbqnjajsjsujss
Answer:
(w^2 - 4w + 16)
Step-by-step explanation:
Note that w^3 +64 is the sum of two perfect cubes, which are (w)^3 and (4)^3. The corresponding factors are (w + 4)(w^2 - 4w + 16).
Therefore,
(w^3 +64)/(4+ w) reduces as follows:
(w^3 +64)/(4+ w) (4 + w)(w^2 - 4w + 16)
--------------------------- = --------------------------------- = (w^2 - 4w + 16)
4 + w 4 + w
Answer:
60% Hope this helped! :)
Step-by-step explanation:
