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Oksana_A [137]
3 years ago
10

Is 30 a reasonable estimate of a quotient for 91,766 ÷ 288? answer if you know please

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
3 0

Answer:

300 would be

Step-by-step explanation:

Inessa [10]3 years ago
3 0

Answer:

No, around 300 would be reasonable.

Step-by-step explanation:

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Can someone explain this to me?
ch4aika [34]
You have to first find the pattern, which in this case we can see that the numbers on the left are being multiplied by 512 to result in the numbers on the right.
next, you have to find the average of 512. you’d probably have to divide 512 by how many hours worked which would be 4. i might be wrong on that though.
3 0
3 years ago
Read 2 more answers
For the following exercises, evaluate the function at the indicated values: f (−3); f (2); f (−a); −f (a); f (a + h).
ser-zykov [4K]

Answer:

5. f(x) = -2x² + 3x  

f(-3) = -2(-3)² + 3(-3) = -27

f(2) = -2(2)² + 3(2) = -2

f(-a) = -2(-a)² + 3(-a) = -2a² - 3a

-f(a) = -[-2a² + 3a] = 2a² - 3a

f(a + h) = -2(a + h)² + 3(a + h) = -2(a² + 2ah + h²) + 3a + 3h = -2a² - 4ah - 2h² + 3a + 3h

6. f(x) = 2|3x - 1|

f(-3) = 2|3(-3) - 1| = 2*10 = 20

f(2) = 2|3(2) - 1| = 2*5 = 10

f(-a) = 2|3(-a) - 1| = 2|-3a - 1|

-f(a) = -(2|3a - 1|) = -2|3a - 1|

f(a + h) = 2|3(a + h) - 1| = 2|3a + 3h - 1|

3 0
3 years ago
8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches
sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that \mu = 32, \sigma = 1.5

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 32}{1.5}

X - 32 = -1.645*1.5

X = 29.5

Heights of 29.5 and below could be a problem.

4 0
3 years ago
Identify the polynomial.<br> x^3-y^3+z
Margarita [4]

Answer:

Cubic trinomial

Step-by-step explanation:

Higest power is 3 and there are 3 terms

4 0
2 years ago
This petite girl, short as can be is gonna jump and be free<br> -Rachie [My R]
suter [353]

for god sake pls are you serious?! i just can't believe! for a st...upi...d reason you got here before me?!? are you upset cuz you can't have what you wanted?!

7 0
3 years ago
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