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Alex73 [517]
4 years ago
9

How can estimating the quotient help you check that your answer to division problem is reasonable?

Mathematics
2 answers:
Sidana [21]4 years ago
4 0
If your answer is near the estimate than ur probably correct

g100num [7]4 years ago
3 0
To find 123 divided 36 with the estimate 120 divided 40 = 3 then use this estimate to help u place the first digit in the quotient
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Do low how to do this if so help me
rodikova [14]
I believe that the answer is 14
8 0
3 years ago
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Can anyone pls sub to my youttube? Its called Yakobu, It would rlly help. :)
quester [9]

Answer:

did it

Step-by-step explanation:

5 0
3 years ago
Divide:(10x²-3x+4)÷(2x-5)
Helen [10]

Answer:

\frac{10x^2-3x+4}{2x-5}=5x+11+\frac{59}{2x-5}

Quotient: 5x+11

Remainder: 59

Step-by-step explanation:

I'm going to do long division.

The bottom goes on the outside and the top goes in the inside.

  Setup:

        ---------------------------------

2x-5 |  10x^2    -3x      +4

  Starting the problem from the setup:

            5x     +11                        (I put 5x on top because 5x(2x)=10x^2)

        ---------------------------------   (We are going to distribute 5x to the divisor)

2x-5 |  10x^2    -3x      +4

        -(10x^2  -25x)                  (We are now going to subtract to see what's left.)

      -----------------------------------

                      22x      +4          (I know 2x goes into 22x, 11 times.)

                                                ( I have put +11 on top as a result.)

                    -(22x     -55)        (I distribute 11 to the divisor.)

                 -----------------------

                                  59          (We are done since the divisor is higher degree.)

The quotient is 5x+11.

The remainder is 59.

The result of the division is equal to:

5x+11+\frac{59}{2x-5}.

We can actually use synthetic division as well since the denominator is linear.

Let's solve 2x-5=0 to find what to put on the outside of the synthetic division setup:

2x-5=0

Add 5 on both:

2x=5

Divide both sides by 2:

x=5/2

Or realize that 2x-5 is the same as 2(x-(5/2)) which you will have to do anyways if you choose this route:

So 5/2 will go on the outside:

5/2  |    10          -3            4

      |                  25         55

         ------------------------------

           10          22        59

So we have:

\frac{10x^2-3x+4}{2x-5}

=\frac{10x^2-3x+4}{2(x-\frac{5}{2})}=\frac{1}{2} \cdot \frac{10x^2-3x+4}{x-\frac{5}{2}}=\frac{1}{2}(10x+22+\frac{59}{x-\frac{5}{2}})

Distribute the 1/2 back:

\frac{10x^2-3x+4}{2x-5}=\frac{10x+22}{2}+\frac{59}{2(x-\frac{5}{2})}

\frac{10x^2-3x+4}{2x-5}=5x+11+\frac{59}{2x-5}

3 0
4 years ago
If A:(1,4,7,8) and b:(4,6,8,9)and c:​
Usimov [2.4K]
Incomplete question please add a image
5 0
3 years ago
5f + 3s +6<br> use f= 6 and s = 7
Luden [163]
57 because 5(6)+3(7)+6 is 30+21+6=57
6 0
4 years ago
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