Question

Try It #3

Answer 1

The distance of the road junction form Timpson is given as 21.57 miles.

We have to solve this using the Pythagoras theorem method

We have AT = $\sqrt{TN^{2}+AN^{2} }$

√60² + 12² = 12√26

∠TMG = LN = 90 degrees

Therefore we have the system

$\frac{TM}{60} = \frac{22}{12\sqrt{26} }$

When we cross multiply we would have to solve for TM

TM = 21.57 miles

Hence the distance of the road junction form Timpson is given as 21.57 miles.

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brainly.com/question/17273444

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