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3 years ago

Find the general solution for cos x = 0, where n is an integer.

1 answer:

6 0

First we solve this equation:
x = cos^-1(0) = pi/2 and 3pi/2

Now, this is the answer for angles between 0 and 2pi

but there are "negative angles" and angles larger than 2pi
so the general solution that includes all of these cases is:

x = pi/2 + n*pi

here n is any integer.

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10-5m=45 gdhehhehdhdh ignore the letters at the end

Lubov Fominskaja [6]

Subtract 10 from each side to get -5m=35
Divide each side by -5 to get m=-7
So m=-7

6 0

3 years ago

Pleaseee help. I’m having a hard time with this problem. Giving away 20 points.

salantis [7]

Answer:

i can't see it is to tinny so i don't know what to do

Step-by-step explanation:

6 0

3 years ago

What is a complete graph.

Kay [80]

Answer:

A complete graph is 100 or over

Step-by-step explanation:

hope this helps G

3 0

1 year ago

To gain a pass a student needs to achieve a mean of at least 60% in eight tests. In the first seven

Tanzania [10]

Step-by-step explanation:

the mean value is the sum of all data points divided by the number of data points.

first we have 7 tests and their mean value :

(t1 + t2 + t3 + t4 + t5 + t6 + t7) / 7 = 54

that means

(t1 + t2 + t3 + t4 + t5 + t6 + t7) = 54 × 7 = 378

in order for the mean value to be at least 60% after 8 tests, we need to add a t8, so that

(t1 + t2 + t3 + t4 + t5 + t6 + t7 + t8) = 60 × 8 = 480

because only then we have

(t1 + t2 + t3 + t4 + t5 + t6 + t7 + t8) / 8 = 60

and the student passes.

so,

(t1 + t2 + t3 + t4 + t5 + t6 + t7) + t8 = 480

378 + t8 = 480

t8 = 480 - 378 = 102%

the student would have to achieve 102% on the 8th test.

which would be normally impossible, but maybe the tests involve some bonus points.

6 0

1 year ago

Which equation is in slope-intercept form and represents a line with slope 0 through the point (2, 3)?

alexandr1967 [171]

I think it would be b) because you're given a slope of 0, so that leaves you with
$y=0x+b$
, resulting into this
$y=b$
You'd be just left with a continuous horizontal line going through the y-axis of 3 since you're passing the point (2,3), where 3 represents the y-value when your slope is at 0.

6 0

2 years ago