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3 years ago

Can you tell me the solution to -3 (p + 1) equal to -18

Mathematics

2 answers:

Alja [10]3 years ago

5 0

Hi there!

The answer to the inequality given is p ≥ 5

To get there follow these steps:
1. Distribute the -3, -3p-3≤-18
2. Add -3 to both sides, {-3p (-3 + 3 = 0) ≤ (-18 + 3 = -15)} = -3p ≤ -15
3. Divide both sides by -3, $\frac{-3p}{-3}$ ≤ $\frac{-15}{-3}$ 
4. The final answer is p ≥ 5

If you need this graphed see below:

-ASIAX Frequent Answerer

Gnom [1K]3 years ago

4 0

-3p-3=-18
-3p=-18+3
-3p=-15
p=5

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4 years ago

What algebraic expression must be added to the sum of 3x2 +4x+8 and 2x2−6x+3 to give 9x2−2x−5 as the result?

Gnom [1K]

4x² - 16 is the algebraic expression that must be added to get the result as 9x²- 2x - 5.

Step-by-step explanation:

The question is asked for the algebraic expression must be added to the sum of 3x²+4x+8 and 2x2−6x+3 to give 9x²- 2x - 5 as the result.

Therefore,

The first step is to find of sum of 3x²+4x+8 and 2x²-6x+3.

To find the sum :

3x²+4x+8

2x²-6x+3

5x²-2x+11

The sum is 5x²-2x+11.

Now, the second step is to subtract 5x²-2x+11 from the result 9x²- 2x - 5.

9x²- 2x - 5

- (5x²-2x+11)

4x² -16

Thus, 4x²-16 is the algebraic expression that must be added with 5x²-2x+11 to get a result of 9x²- 2x - 5.

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3 years ago

Which function has an inverse function?

daser333 [38]

Answer: Option B

Step-by-step explanation:

By definition, only those functions that are one to one have an inverse function.

A function is one by one if there are not two different input values, $x_1$ and $x_2$ , that have the same output value y

Note that the function $f(x)= \frac{|x+3|}{5}$ is not a one-to-one function

When x=2 $f(x)= \frac{|2+3|}{5}=1\ ,\ \ y=1$

When x=8 $f(x)= \frac{|-8+3|}{5}=1\ \ ,\ y=1$

Note that the function $f(x)= \frac{x^4}{7}+ 27$ is not a one-to-one function

When x=1 $f(x)= \frac{(1)^4}{7}+27\ ,\ \ y=\frac{190}{7}$

When x=-1 $f(x)= \frac{(-1)^4}{7}+27\ ,\ \ y=\frac{190}{7}$

Note that the function $f(x)= \frac{1}{x^2}$ is not a one-to-one function

When x=1 $f(x)= \frac{1}{(1)^2}\ ,\ \ y=1$

When x=-1 $f(x)= \frac{1}{(-1)^2}\ ,\ \ y=1$

Then the answer is the option B.

You can verify that The function $f (x) = x ^ 5-3$ is a one-to-one function and therefore its inverse is a function

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3 years ago

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3 years ago

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