Answer:
Step-by-step exExplanation:
Solve:
3
x
2
−
4
x
−
5
=
0
is a quadratic equation in standard form:
a
x
2
+
b
x
+
c
,
where:
a
=
3
,
b
=
−
4
,
c
=
−
5
Quadratic formula
x
=
−
b
±
√
b
2
−
4
a
c
2
a
Plug in the known values.
x
=
−
(
−
4
)
±
√
(
−
4
)
2
−
4
⋅
3
⋅
−
5
2
⋅
3
Simplify.
x
=
4
±
√
76
6
Prime factorize
76
.
x
=
4
±
√
2
2
×
19
6
Apply rule:
√
a
2
=
a
x
=
4
±
2
√
19
6
Simplify.
x
=
2
±
√
19
3
Solutions for
x
.
x
=
2
+
√
19
3
,
2
−
√
19
3
Related questions
How do you know how many solutions
2
x
2
+
5
x
−
7
=
0
has?
What is the Quadratic Formula?
planation:
Answer:
Given:
,
,
,
formed by two intersecting segments.
In the given figure;
Linear pair states that a pair adjacent angle formed when two lines intersect.
Then by definition of linear pairs,
and
forms a linear pair
Also,
and
forms a linear pair.
Linear pair postulates states that the two angle that forms a linear pair are supplementary(i,e add up to 180 degree).
Then by linear pair postulates;

and

Substitution property of equality states that if x =y then, x can be substituted in for y or vice -versa.
then by substitution property of equality:

Addition property of equality states that:
if x =y, then x + z = y+ z
By addition property of equality:
hence proved!
Answer:
75%
88.89%
Step-by-step explanation:
Given :
Mean = 70
Standard deviation = 12
Since the data is said to be extremely skewed, we apply Chebyshev's theorem rather than the empirical rule :
The minimum proportion of observation between 46 and 94
Chebyshev's theorem :
1 - 1 / k²
k = number of standard deviations from the mean
k = (94 - 70) / 12 = 24 / 12 = 2
Hence, we have ;
1 - 1/2²
1 - 1/4
1 - 0.25 = 0.75
Hence, The minimum proportion of observation between 46 and 94 is 75%
Between 36 and 106 :
k = (106 - 70) / 12 ;
k = 36/12 = 3
Hence,
1 - 1/3² = 1 - 1/9 = 8/9 = 0.8888 = 88.89%
The minimum proportion of observation between 34 and 106 is 88.89%
FACTORISATION IS BASICALLY FINDING LIKE-TERMS.
1. FIND THE HCF OF 8. HERE, THE HCF IS 8. ALSO, CHECK ALL THE LIKE-TERMS. LIKE-TERMS ARE OUTSIDE THE BRACKET AND UNLIKE TERMS ARE INSIDE.
2. ADD THE TERMS IN THE BRACKET AND THE TERMS OUTSIDE THE BRACKET FROM STEP 1.
8x + 8y + rx + ry
1. 8 (x + y) + r (x + y)
2. (x +y) (8+r)