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mote1985 [20]
3 years ago
14

I NEED HELP ASAP!!!!!!!!!!!!!!!!

Mathematics
1 answer:
klio [65]3 years ago
4 0

Answer:

24/10 = 12/5

Step-by-step explanation:

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Help Me for number 1 & 2
mafiozo [28]
This may not be correct but Georgia will be about nine if u subtract 6 from 15... And as for Jerry, if he swims for 4 hours, at 2 miles, he might be swimming 480 miles.. 2x60 (aka and hour x 2) 120.. Do that 4 times and u end up with about 480.. So sorry if I'm wrong
6 0
3 years ago
What's the value of <br> The 1s in 5114
MissTica
The one near the five is in the hundreds place and the one near the 4 is in the tenth place. 

Feel free to message me if you need help on another problem. 
8 0
3 years ago
Read 2 more answers
What is if you do 3x10
scZoUnD [109]

Answer:

30

Step-by-step explanation:

10 x 3 = 30

6 0
3 years ago
Over the course of the school year, you keep track of how much snow falls on a given day and whether it was a snow day. Your dat
Free_Kalibri [48]

Answer:

Probability of the day to be a snow day is 0.34

Step-by-step explanation:

We have the data,

Out of 21 which had less than 3 inches of snow, 5 were snow days.

Out of 8 days which had more than 3 inches of snow, 6 were snow days.

So, we get,

Total number of days = 21 + 8 = 29

Total number of snow days = 5 + 6 = 11

Thus, the probability that the day will be a snow day is \frac{11}{29} i.e. 0.34

Hence, the probability of the day to be a snow day is 0.34.

5 0
3 years ago
if the recommended daily allowance for vitamin c is 60 mg per day and there are 70 mg of vitamin C per 100 g orange, how many 3.
noname [10]

Answer: 7

Step-by-step explanation:

Given : The recommended daily allowance for vitamin c is 60 mg per day .

Then, for one whole week , the recommended allowance for vitamin c will be :-

7\times60=420\text{ mg}

Also, there are 70 mg of vitamin C per 100 g orange.

1 g = 1000 ml

The proportion of Vitamin C in 100 g = \dfrac{70}{100000}=0.0007

1 oz =28.3495 grams

Then, 3\ oz= 3\times28.3495=85.0485 \text{ gm}=85048.5\ mg

Then, amount of vitamin C in 85048.5 mg = 0.0007\times85048.5=59.53395\approx59.53\ mg

Then, the number of oranges have to eat each week to meet this requirement= \dfrac{420}{59.53}\approx7

Hence,  about 7 oranges you would have to eat each week to meet this requirement.

8 0
3 years ago
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