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Stells [14]
3 years ago
14

Represent the following sentence as an algebraic expression, where "a number" is the letter x. You do not need to simplify.

Mathematics
1 answer:
Tresset [83]3 years ago
7 0
5-x^2 would be your expression
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How to make 4.5 into a fraction
Zepler [3.9K]
The fraction is 4 1/2. Just convert the decimal into a fraction. 50/100 is the same as 5/10 which is the same as 1/2.
5 0
3 years ago
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The graph shows a probability distribution. What is P(X<5)
Thepotemich [5.8K]

Answer:

P(x < 5) = 0.70

Step-by-step explanation:

Note:  The area under a probability "curve" must be = to 1.

Finding the sub-area representing x < 5 immediately yields the desired probability.

Draw a dashed, vertical line through x = 5.  The resulting area, on the left, is a trapezoid.  The area of a trapezoid is equal to:

 (average length)·(width, which here is:

  2 + 5

----------- · 0.02  =  (7/2)(0.2) =  0.70

      2

Thus, P(x < 5) = 0.70

7 0
3 years ago
2thousands pluse 14hundreds
snow_tiger [21]
2.000 pluse 4.00=600.000
4 pluse 2=6
thousand pluse hundreds=hundre thousandths


3 0
3 years ago
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Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f
tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative f^{l} (x) and equating zero

iii) solve and find 'x' values

iv) Find second derivative f^{ll}(x) >0 then find the minimum value at x=a

v) Find second derivative f^{ll}(x) then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative f^{l} (x) and equating zero

  f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)

f^{l}(x) = \frac{1}{x^2+1} (2x)  ……………(1)

f^{l}(x) = \frac{1}{x^2+1} (2x)=0

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}

on simplification , we get

f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}

put x= 0 we get f^{ll}(0) = \frac{2}{(1)^2}   > 0

f^{ll}(x) >0 then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

5 0
3 years ago
What are the coordinates of the terminal point determined by θ=7π/6?
erma4kov [3.2K]
Cos ( theta ) = cos 7π/6 = -√3/2
sin ( Theta ) = sin 7π/6 = -1/2
Coordinates of the terminal points are: ( -√3/2,  -1/2 ) 
6 0
3 years ago
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