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bulgar [2K]
3 years ago
6

Find the number of possible choices for a 3-digit PIN (personal identification number) if the digits CAN be repeated.

Mathematics
1 answer:
Lelechka [254]3 years ago
5 0
10*10*10 = 1000 possible choices
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On the real number line the origin is assigned the number​ ___.
Murrr4er [49]

Answer:

0

Step-by-step explanation:

The points on a number line are called coordinates. The zero point is called the origin. The numbers to the right of the origin are positive numbers; the numbers to the left of the origin are negative numbers.

4 0
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Which of the following rules should be use to find the area of a triangle?
lbvjy [14]

The area of a triangle is half the product of the base and the height.

Since multiplication is commutative, the following expressions are equivalent:

A=(bh)\cdot \dfrac{1}{2} = \dfrac{b}{2}\cdot h = \dfrac{h}{2}\cdot b

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2 years ago
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John and Martha are contemplating having children, but John’s brother has galactosemia (an autosomal recessive disease) and Mart
Rina8888 [55]
<h2>Answer:</h2>

Probability=\frac{1}{24}

<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

Now,

Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

So,

Probability for the child to have disease will be = 1/2

Now, again the child's child (Martha) probability for having the disease is = 1/2.

Therefore,

<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is \frac{1}{24}</u></em>

3 0
3 years ago
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