Answer:
-1 and -4
Step-by-step explanation:
-1 + -4 = -5
-1 times -4 = 4
give brainiest please!
hope this helps ;)
Answer:
= 78
= 3.5
Step-by-step explanation:
First we need to find
.
We can use the equation
to solve for
.
We can then change that equation to
, since the Commutative Property of Addition says that you can have any addition in any order.
Now, we can solve the equation.

Now that we solved
, we can now solve for
.
Since 25 equals
, we can solve the equation
.
Here is how you solve it:

Since
equals 3.5, which is the simplest form, that is the answer.
Hope this helps, and please mark me brainliest! :)
9514 1404 393
Answer:
x = -3/2
Step-by-step explanation:
The zeros of the function are the values of x that make the factors zero:
x = -4, x = 1
The axis of symmetry is the vertical line halfway between these zeros.
x = (-4 +1)/2 = -3/2
The equation of the axis of symmetry is x = -3/2.
Answer:
6 papayas and 11 pineapples
Step-by-step explanation:
So, we need to find an answer of how many papayas and pineapples she bought, and we only spent $48.
So, papayas are $2.50 each, and Pineapples are $3.00 each and we only bought 17 fruits total.
lets try 8 papayas, and 9 Pineapples.
$2.50 x 8 = $20.00 total on Papayas
$3.00 x 9 = $27.00 total on Pineapples.
That would only be $47 spent total.
Lets try 10 papayas and 7 pineapples.
$2.50 x 10 = $25.00
$3.00 x 7 = $21.00
That would only be a total of $26 spent.
Lets try 6 papayas and 11 pineapples.
$2.50 x 6 = $15.00
$3.00 x 11 = $33.00
This would be a total of $48 spent.
Answer: provided in the explanation segment
Step-by-step explanation:
here i will give a step by step analysis of the question;
A: Optimization Formulation
given Xij = X no. of units of product i manufactured in Plant j, where i = 1,2,3 and J = 1,2,3,4,5
Objective function: Minimize manufacturing cost (Z)
Z = 31 X11 + 29 X12 + 32X13 + 28X14 + 29 X15 + 45 X21 + 41 X22 + 46X23 + 42X24 + 43 X25 + 38 X31 + 35 X32 + 40X33
s.t
X11 + X12 + X13 + X14 + X15 = 600
X21 + X22 + X23 + X24 + X25 = 1000
X31 + X32 + X33 = 800
X11 + X21 + X31 <= 400
X12 + X22 + X32 <= 600
X13 + X23 + X33 <= 400
X14 + X24 <= 600
X15 + X25 <= 1000
Xij >= 0 for all i,j
B:
Yes, we can formulate this problem as a transportation problem because in transportation problem we need to match the supply of source to demand of destination. Here we can assume that the supply of source is nothing but the manufacturing capability of plant and demand of destination is similar to the demand of products.
cheers i hope this helps!!