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Zina [86]
3 years ago
5

Jared drove a distance of 165 miles to billings last weekend, which used 11 gallons of gas. How many gallons of gas will he need

to drive to denver, 735 miles away?
Mathematics
1 answer:
blondinia [14]3 years ago
3 0

Answer:

8550

Step-by-step explanation:

1. you need to figure out how many time 11 goes into 165 which is 15 then you need to get the 15 and multiply it by 570.

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A construction company is strung up signs on 4 mile of the road.. if the company places a sign every 1/8 of a mile, how many sig
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"A construction company is stringing up signs ... "


Divide 4 miles by 1/8 mile:


4 miles

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(1/8) mile per sign

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Use the graph of f(x) to write its equation. y! X​
e-lub [12.9K]

Answer:

y = |x + 2|

Step-by-step explanation:

given the straight shape, it must be a linear function, but the "bend" in it indicates that an absolute value is being used.

So to start we can say: y = |x|

But that's not sufficient, as it would show that bend being at 0, 0. Instead, we need to translate it two units to the left, giving us:

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because
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8 0
2 years ago
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A person bikes 2 1/2 miles at a constant rate in 1/8 of an hour. What distance, in miles,does the person bike in an hour?
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The person bikes 20 miles in an hour.

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A librarian has 4 identical copies of Hamlet, 3 identical copies of Macbeth, 2 identical copies of Romeo and Juliet, and one cop
lesantik [10]

Answer:

The number of distinct arrangements is <em>12600</em><em>.</em>

Step-by-step explanation:

This is a permutation type of question and therefore the number of distinguishable permutations is:

n!/(n₁! n₂! n₃! ... nₓ!)

where

  • n₁, n₂, n₃ ... is the number of arrangements for each object
  • n is the number of objects
  • nₓ is the number of arrangements for the last object

In this case

  • n₁ is the identical copies of Hamlet
  • n₂ is the identical copies of Macbeth
  • n₃ is the identical copies of Romeo and Juliet
  • nₓ = n₄ is the one copy of Midsummer's Night Dream

Therefore,

<em>Number of distinct arrangements =  10!/(4! × 3! × 2! × 1!)</em>

<em>                                                         = </em><em>12600 ways</em>

<em />

Thus, the number of distinct arrangements is <em>12600</em><em>.</em>

4 0
2 years ago
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