"quadration?" "quadratic equation?"
Write out the general vertex form and then plug in the given info:
y = a(x-h)^2 + k
Vertex at (3,3): y = a(x-3)^2 + 3
curve passes thru (5,11): 11 = a(5-3)^2 + 3
11 = a(2)^2 + 3 = 4a + 3 = 11, or a = 2
Then the equation of this parabola is
y = 2(x-3)^2 + 3.
check: Does this pass thru (5,11)? Is 11 = 2(5-3)^2 + 3 true?
Is 11 = 2(4)+3 true? YES
3, assuming 2x2 is 2x squared, u will get
4 + 6x3 - 10x2
So 3 terms
Answer:
D
Step-by-step explanation:
Answer:
the line defined by the equation x = -3 is parallel to x = -18, and contains the point (-3,5)
Step-by-step explanation:
Notice that this is a vertical line that goes crosses the x axis at x= -18.
A line parallel to this will also be of the form x = "constant value", meaning that all points in the line must have a fixed x-value. If the line has to go through the point (-3, 5), that that fixed x-value must be "-3".
Therefore the line defined by the equation x = -3 is parallel to x = -18, and contains the point (-3,5)
He should choose a) an annual raise of $3500.
This is because if you take 5% of $60,000 its only $3,000