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3 years ago

1: Plot the graph of the equation 2x-3y=6 and 2x+y=-10 and intercept the result.

1 answer:

5 0

To graph the equations, rewrite the equations written in standard form to slope-intercept form of the equation.

$y=mx+b\\\\ 2x-3y=6\\ 2x+y=-10 \\\\3y= 2x- 6\ \ / :3\\ y=-2x-10 \\\\y= \frac{2}{3}x- 2 \\ y=-2x-10$

$Answer : \\ \\The \ lines \ intersect \ when \ x = -3 \ and \ y = -4$

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Your math teacher tells you that the next test is worth 100 points and contains 38 problems. Multiple choice questions are worth

Westkost [7]

eight 5 and thirty 2

Step-by-step explanation:

8 times 5 = 40 and then 30 times 2 = 60

40+60= 100

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3 years ago

Sequence: 1,5,13,25 Find nth term (Equation/formula thingy) Need answer ASAP

masha68 [24]

Answer:

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1 year ago

Find from u. -12u = -24

Bingel [31]

Well, to find u, we have to remove all that is attached to it so the equation can just be u=...
To find u, you have to remove what is attached to it, and that is -12. Then you have to look at the relationship between the -12 and u. The relationship is multiplication, and the opposite of multiplication is division, so all you have to do is divide both sides by -12. So;
-12u/-12=-24/-12
The -12 cancels the -12, leaving u and the - in 12 cancels the - in 24. Leaving 24/12. And that is 2. Written as;
u=2
Hope i helped. If you have any more problems, let me know.

5 0

3 years ago

Read 2 more answers

ПОЖАЛУЙСТА ПОМОГИТЕ РЕШИТЬ ДАЮ 23 ОЧКА!!!

posledela

(Простите, пожалуйста, мой английский. Русский не мой родной язык. Надеюсь, у вас есть способ перевести это решение. Если нет, возможно, прилагаемое изображение объяснит достаточно.)

Use the shell method. Each shell has a height of 3 - 3/4 y ², radius y, and thickness ∆y, thus contributing an area of 2π y (3 - 3/4 y ²). The total volume of the solid is going to be the sum of infinitely many such shells with 0 ≤ y ≤ 2, thus given by the integral

$\displaystyle 2\pi \int_0^2 y \left(3-\frac34 y^2\right) \,\mathrm dy = 2\pi \left(\frac32 y^2 - \frac3{16} y^4\right)\bigg|_0^2 = 6\pi$

Or use the disk method. (In the attachment, assume the height is very small.) Each disk has a radius of √(4/3 x), thus contributing an area of π (√(4/3 x))² = 4π/3 x. The total volume of the solid is the sum of infinitely many such disks with 0 ≤ x ≤ 3, or by the integral

$\displaystyle \pi \int_0^3 \left(\sqrt{\frac43x}\right)^2 \,\mathrm dx = \frac{2\pi}3 x^2\bigg|_0^3 = 6\pi$

Using either method, the volume is 6π ≈ 18,85. I do not know why your textbook gives a solution of 90,43. Perhaps I've misunderstood what it is you're supposed to calculate? On the other hand, textbooks are known to have typographical errors from time to time...

8 0

3 years ago

This figure is the net

Afina-wow [57]

I wanna say B but i don’t remember i had that question before though

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3 years ago

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