Answer:
Yes,there is a significant association shell weight and the widths of the opercula
Step-by-step explanation:
Using a correlation Coefficient calculator :
Given the data above :
The Coefficient of correlation(r) obtained is :
0.7632
Obtaining the test statistic :
T = r² / √(1 - r²) / (n - 2)
T = 0.7632² / √(1 - 0.7632²) / (10 - 2)
T = 0.58247424 / 0.2284528
Test statistic = 2.550
The Pvalue from r score , N = 10
Pvalue(0.7632, 10) = 0.01022
α = 0.05
If Pvalue < α ; reject H0
Pvalue < α ; We conclude that there is a significant association shell weights and the widths of the opercula