1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
borishaifa [10]
4 years ago
6

The inequality 6 - 2/3x < x - 9 is equivalent to...

Mathematics
1 answer:
Dafna11 [192]4 years ago
6 0

Start with

6-\dfrac{2}{3}x

Add 9 to both sides

15-\dfrac{2}{3}x

Add \frac{2}{3}x to both sides

15

Multiply both sides by 3/5

9

Which is the same as

x>9

You might be interested in
Help please with this​
PolarNik [594]

Answer:

C. 54

Step-by-step explanation:

I just answered the expression as i went and I got 54.

4 0
3 years ago
Read 2 more answers
Which of the following ordered pairs could Maggie add to the graph
Minchanka [31]

Answer:

(0,0) it's also the origin.

3 0
4 years ago
Read 2 more answers
Which of the following fractions is not in simplest form?<br> 6/21<br> 3/14<br> 0 712<br> 10/17
zhuklara [117]
The answer is 6/21 is not in its simplest form as you can still divide them both by 3
8 0
3 years ago
If you were asked to convert 75 m/s to km/hr, which conversation factors would you need to use. Select all that apply.
Vilka [71]

Answer:

You need to use A, B, and C.

Step-by-step explanation:

Let's treat the units as variables. I'll illustrate why in a moment.

75 m/s =\frac{75m}{1s} \\\\\frac{75m}{1s}*\frac{1km}{1000m}=\frac{75m*km}{1000m*s}\\\\\frac{75m*km}{1000m*s}*\frac{60s}{1min}=\frac{(75*60)m*km*s}{1000m*s*min}\\\\\frac{4500m*km*s}{1000m*s*min}*\frac{60min}{1h}=\frac{4500m*km*s*min}{1000m*s*min*h}

Now, as you can see, we have a giant mess of units to deal with. This is where we can treat the units like separate variables and use a bit of algebra to make our lives easier:

\frac{4500m*km*s*min}{1000m*s*min*h}=\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}\\\\\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}=\frac{4500}{1000}*\frac{m}{m}*\frac{km}{1}*\frac{s}{s}*\frac{min}{min}*\frac{1}{h}\\\\\frac{4500}{1000}*\frac{m}{m}*\frac{km}{1}*\frac{s}{s}*\frac{min}{min}*\frac{1}{h}=\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}=\frac{4500}{1000}*1*\frac{km}{1}*1*1*\frac{1}{h}\\\\\frac{4500}{1000}*1*\frac{km}{1}*1*1*\frac{1}{h}=\frac{4500}{1000}*\frac{km}{h}\\

\frac{4500}{1000}*\frac{km}{h}=\frac{45}{1}*\frac{km}{h}=45 \frac{km}{h}

So, backtracking through that entire mess, we had to use \frac{1km}{1000m} ,\frac{60s}{1min} ,\frac{60min}{1h}.

These correspond to the options of A, C, and B accordingly.

So you need to use A, B, and C.

8 0
3 years ago
What is the fraction of 2 1/4
icang [17]

Answer:

9/4

Step-by-step explanation:

2 1/4 = 9/4 From mixed fraction to an improper fraction: "the numerator of the improper fraction" = "denominator" xx "the whole number" + "the numerator of the mixed fraction" The denominator remains as it is. So 2 1/4 = (4 xx 2 + 1)/4 = 9/4

3 0
3 years ago
Read 2 more answers
Other questions:
  • NEED HELP ASAP
    13·1 answer
  • A radio tower is located 300 feet from a building. From a window in the building, a person determines that the angle of the elev
    15·1 answer
  • Can you please help me with #39 please!!?? Please explain part b. Please!!!!
    14·1 answer
  • FREE POINTS AND BRAINLIEST IF YOU GET THESE 2 TRIVIA QUESTIONS RIGHT!!!:
    14·2 answers
  • a person was born on may 14, 40 B.C. and died on may 14, 30 A.D. how many years did this person live.
    7·1 answer
  • A group of numbers symbols and operate is known as a
    14·1 answer
  • How to find the volume of a cone with its base in algebra​
    5·1 answer
  • A variable needs to be eliminated to solve the system of equations below. Choose the
    12·1 answer
  • Please help! i think the answer is 12 but any verification would be greatly appreciated!
    9·2 answers
  • Jackie did not have the ______ to play for any team that wanted him.
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!