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aev [14]
3 years ago
7

If you were asked to convert 75 m/s to km/hr, which conversation factors would you need to use. Select all that apply.

Mathematics
1 answer:
Vilka [71]3 years ago
8 0

Answer:

You need to use A, B, and C.

Step-by-step explanation:

Let's treat the units as variables. I'll illustrate why in a moment.

75 m/s =\frac{75m}{1s} \\\\\frac{75m}{1s}*\frac{1km}{1000m}=\frac{75m*km}{1000m*s}\\\\\frac{75m*km}{1000m*s}*\frac{60s}{1min}=\frac{(75*60)m*km*s}{1000m*s*min}\\\\\frac{4500m*km*s}{1000m*s*min}*\frac{60min}{1h}=\frac{4500m*km*s*min}{1000m*s*min*h}

Now, as you can see, we have a giant mess of units to deal with. This is where we can treat the units like separate variables and use a bit of algebra to make our lives easier:

\frac{4500m*km*s*min}{1000m*s*min*h}=\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}\\\\\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}=\frac{4500}{1000}*\frac{m}{m}*\frac{km}{1}*\frac{s}{s}*\frac{min}{min}*\frac{1}{h}\\\\\frac{4500}{1000}*\frac{m}{m}*\frac{km}{1}*\frac{s}{s}*\frac{min}{min}*\frac{1}{h}=\frac{4500}{1000}*\frac{m*km*s*min}{m*s*min*h}=\frac{4500}{1000}*1*\frac{km}{1}*1*1*\frac{1}{h}\\\\\frac{4500}{1000}*1*\frac{km}{1}*1*1*\frac{1}{h}=\frac{4500}{1000}*\frac{km}{h}\\

\frac{4500}{1000}*\frac{km}{h}=\frac{45}{1}*\frac{km}{h}=45 \frac{km}{h}

So, backtracking through that entire mess, we had to use \frac{1km}{1000m} ,\frac{60s}{1min} ,\frac{60min}{1h}.

These correspond to the options of A, C, and B accordingly.

So you need to use A, B, and C.

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Answer: 1\dfrac{11}{12}\text{ pounds}

Step-by-step explanation:

The complete question is provided in the attachment.

Given, Amount blueberry jelly beans= 1\dfrac{1}{4} pounds

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Amount lemon jelly beans = 2\dfrac{1}{3}pounds

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Total jelly beans she bought = Amount blueberry jelly beans + Amount lemon jelly beans

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She has left 1\dfrac{11}{12}\text{ pounds} of jelly beans.

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