1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
matrenka [14]
3 years ago
7

The price of a wallet is 31.95 and the sales tax is 7.5%

Mathematics
1 answer:
rewona [7]3 years ago
5 0
The sales tax is $2.40
So the final price is $34.35
You might be interested in
Someone pls help asap this is supposed to be done it 3 min
insens350 [35]

Step-by-step explanation:

$75      30%      0.70(75) = x      $52.50

$18       65%      0.35(18) = x      $6.30

$60      30%     0.70x = 42        $42

$35       20%     0.80x = 28       $28

$150      25%     0.75(150) = x     $112.50

6 0
2 years ago
Read 2 more answers
Pls help asapp picture attached
Olin [163]

Answer:

50

Step-by-step explanation:

Angle 1 is 110.

Angle 3 is 2x plus 10.

Angle 1 and 3 are vertically opposite angles.

And vertically opposite angles r equal.

Which means, angle 1=angle 3,and angle 2=angke 4.

Here we only Need angle 2 and 3.

Angke 2= angle 3.

Which is 2x plus 10=110.

Therefore 2x=110-10=100

Therefore x = 100÷2=50

There u have it ma'am.

3 0
3 years ago
Read 2 more answers
Please help !!<br>[90 points if correct]​
3241004551 [841]

Answer:

2201.8348 ; 3 ; x / (1 + 0.01)

Step-by-step explanation:

1)

Final amount (A) = 2400 ; rate (r) = 6% = 0.06, time, t = 1.5 years

Sum = principal = p

Using the relation :

A = p(1 + rt)

2400 = p(1 + 0.06(1.5))

2400 = p(1 + 0.09)

2400 = p(1.09)

p = 2400 / 1.09

p = 2201.8348

2.)

12000 amount to 15600 at 10% simple interest

A = p(1 + rt)

15600 = 12000(1 + 0.1t)

15600 = 12000 + 1200t

15600 - 12000 = 1200t

3600 = 1200t

t = 3600 / 1200

t = 3 years

3.)

A = p(1 + rt)

x = p(1 + x/100 * 1/x)

x = p(1 + x /100x)

x = p(1 + 1 / 100)

x = p(1 + 0.01)

x = p(1.01)

x / 1.01 = p

x / (1 + 0.01)

7 0
3 years ago
What is 0.77 estimated
galina1969 [7]
The answer would be .80 or it may be 1
5 0
2 years ago
Read 2 more answers
The wildflowers at a national park have been decreasing in numbers. There were 1200 wildflowers in the first year that the park
bonufazy [111]

Year      New flowers

1                 1200

2                 300

3                   75

There were 1200 wildflowers in the first year that the park started tracking them. Since then, there have been one fourth as many new flowers each year

Initially there are 1200 flowers and start decreasing by \frac{1}{4}

So first term is 1200 and common ratio is \frac{1}{4}.

Its a geometric sequence so summation becomes

i =1∑ ∞ 1200(\frac{1}{4})^{i-1}

Now we find the sum

We use sum formula

Sum = \frac{a}{1-r}

Where a is the first term , a= 1200

r is the common ratio , r= 1/4

Sum = \frac{1200}{1-(\frac{1}{4})}

Sum = \frac{1200}{\frac{3}{4}}

Sum = 1600 wildflowers

4 0
3 years ago
Other questions:
  • for the past hour, olive observed the license plates of the cars passing by her house she saw 120 from New York 355 from New Jer
    6·2 answers
  • Find the markup on the following item. A candy bar costing $0.52 and selling for $0.79. 0.27 0.41 0.66 1.31
    10·2 answers
  • A calculus student takes a 20-question, multiple choice test with 5 answer choices for each question. find the mean and standard
    10·1 answer
  • What times what equals 120
    7·1 answer
  • Find the quotient for 5/7 ÷7/10=
    8·2 answers
  • How to solve 1/4 - -4/3 - -1 2/9
    15·1 answer
  • Which one is not a characteristic of all parallelograms?
    12·1 answer
  • I need help quick- Thanks btw :&gt;
    11·1 answer
  • Ryan wrote a number on his paper. His number rounds to 350 when rounded to the nearest ten. His number rounds to 300 when rounde
    15·1 answer
  • TRUE or FALSE: Observational studies are used to determine causality between explanatory and response variables.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!