Question

A study of six hundred adults found that the number of hours they spend on social networking sites each week is normally distributed with a mean of 17 hours. the population standard deviation is 6 hours. what is the margin of error for a 95% confidence interval? 0.134 0.220 0.313 0.480

Answer 1

Answer:

0.48

Step-by-step explanation:

Given : Mean = 17 hours

            Standard deviation = 6 hours

            n = population size =600

To Find: what is the margin of error for a 95% confidence interval?

Solution:

n= 600

$\sigma = 6$

z = 1.96 for a 95 % confidence interval;

Margin of error formula:

$ME=\frac{z \times \sigma}{\sqrt{n}}$

Substitute the values

$ME=\frac{1.96 \times 6}{\sqrt{600}}$

$ME=0.48$

Hence the margin of error for a 95% confidence interval is 0.48

Answer 2

The answer is C. 0.313