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wariber [46]
3 years ago
15

6th grade math plz help me

Mathematics
1 answer:
anastassius [24]3 years ago
3 0
1) 8 41/48
2) 9 16/27
3) 41 2/5
4) 13 55/63
hope this helps x
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Armando is baking 36 batches of brownies for the bake sale. Each batch of brownies takes cups of flour. What is a reasonable est
Goshia [24]

Answer:

Well, let's assume that "cups" = 3 cups of flour.

Step-by-step explanation:

First, multiply 3x36.

If for some reason this is incorrect, try 2 cups instead of 3. Both are reasonable measurements when it comes to baking.

8 0
3 years ago
7 with the exponent of 3 times 9 with the exponent of 4 minus 2
gayaneshka [121]

Answer:

Step-by-step explanation:

7 with exp 3 times 9 with exp 4 minus 2=

343 times 6561 minus 2=

2250421

4 0
3 years ago
Heather is saving for retirement and has been doing a lot of research on how much she should put aside each month. The newest ar
tino4ka555 [31]
If Heather puts in 1.36% of her salary into a retirement account and she makes $63,000 in a year, this can be solved by 1.36% x 63000. First convert 1.36% into a decimal. To do this, divide by 100.

1.36/100=0.0136

1.36% x 63000
=0.0136 x 63000
=856.8
Heather would put $856.8 in for the whole year. To find how much per month, divide by 12.

856.8/12=71.<span>4
</span>Rounded to the nearest dollar is $71.

Heather would put $71 into a retirement account each month.
<em>
</em><em>Note: This was solved by multiply the percent and then dividing by 12 months. You could also do this by dividing by 12 months first and then multiplying the percent.</em>


6 0
3 years ago
What is the avrege of 4 1/2 3 1/3 2 and 2 1/6
Goryan [66]
2.4 should be your answer
7 0
2 years ago
Pls help me I rlly don’t get it :(
zhenek [66]

Step-by-step explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

Let's start with #12.  The hypotenuse is 18.  The side adjacent to ∠B is 6.  Since we have the adjacent side and hypotenuse, we should use cosine.

cos B = 6/18

Solving for B:

B = cos⁻¹(6/18)

Using a calculator:

B ≈ 70.5°

Now let's do #14.  The side adjacent to ∠B is 19, and the side opposite of ∠B is 22.  Since we have the adjacent side and opposite side, we should use tangent.

tan B = 22/19

Solving for B:

B = tan⁻¹(22/19)

Using a calculator:

B ≈ 49.2°

8 0
3 years ago
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