Answer:
Explanation:
N₂ + 3 H₂ → 2 NH₃
1 mole 3 moles 2 moles
3.45 moles 10.35moles 6.90 moles
So 3.45 moles of nitrogen will require 10.35 moles of hydrogen
But hydrogen available is only 4.85 so this gas is the limiting reagent and product will be formed according to its mass .
a )
3 moles of hydrogen can form 2 moles of ammonia
4.85 moles of hydrogen will form 2 x 4.85 / 3 moles of ammonia
= 3.23 moles .
b ) hydrogen is the limiting reagent .
c ) Excess reactant is nitrogen
3 moles hydrogen need 1 mole of nitrogen
4.85 moles of hydrogen will need 4.85 / 3 moles of nitrogen
= 1.62 moles of nitrogen .
excess nitrogen = 3.45 - 1.62
= 1.83 moles.
